Filter löschen
Filter löschen

projectile question (calculate return time and compare them)

1 Ansicht (letzte 30 Tage)
Zeynep Toprak
Zeynep Toprak am 1 Mär. 2020
Kommentiert: darova am 1 Mär. 2020
I Have a question from a textbook
where some equations are written wrong. The correct versions of them are as follows:
v(t)=(-mg/k)+(v0+(mg/k))*(1-exp(-kt/m))
y(t)=-(m-g-t/k)+(m/k)(v0+(mg/k))(1-exp(-kt/m))
for part-c
v_bar = - gt +v0
y_bar = - ((gt^2)/2) + v0t
I do the first and second parts (a, b) as follows. But I am not definitely sure about my results.
In addition to this, I could not create any code for part-c. Please I'm asking for a help to do such type question.
function projectile = max_height( m, k )
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
g = 9.8;
v0 = 25;
t = 0:0.1:12;
v = - (m*g/k) + ((v0 + (m * g/k)) * exp(- k * t /m));
y = - (m*g*t/k) +((m/k)*(v0 +(m*g/k))*(1-exp(- k * t /m)));
plot(t,y);
[max_height, t] = max(y)
end
  7 Kommentare
Zeynep Toprak
Zeynep Toprak am 1 Mär. 2020
v(t)=0. Then I will find the root of v(t)=0 for t. That's, I will draw t from v(t)=0. Right?
darova
darova am 1 Mär. 2020
I believe that you should find it numerically. But velocity will never be 0
MATLAB doesn't know where is the ground
You can use find to find first negative value
plot(t,y);
ix = find(y < 0,1);
hold on
plot(t(ix),y(ix),'or')
hold off

Melden Sie sich an, um zu kommentieren.

Antworten (0)

Kategorien

Mehr zu Mathematics finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by