Hi, I have this code which I am using to find index of variable a from an array b
a = 2;
b =[ 1 2 3 4 5 6 7 8 9 10];
for i = 1:1:size(b,2)
if (find (a == b))
[~,zq(i)] = (min(b(i)- a));
end
end
The problem is the result "zq", in which I am getting all ones, so I donot know the position, where a is being matched.
Does any one know?

2 Kommentare

Alex Sune
Alex Sune am 26 Feb. 2020
You are obtaining all ones because "b(i)- a" is scalar and the minimum value of a scalar is allways itself.
madhan ravi
madhan ravi am 26 Feb. 2020
Second Alex.

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Bhaskar R
Bhaskar R am 26 Feb. 2020

2 Stimmen

zq = find(b == a)

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