How to save each term from a sum
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clear
n = input('Number of terms: ');
terms = 0;
for n = 1:n
terms=terms + (sum(1/(n^2)));
end
pi1=sqrt(6*terms);
fprintf('the estimate for pi is %g.\n',pi1);
errorF = ((pi1-pi)/pi)*100;
fprintf('the percentage error is %g.\n',errorF);
Hi so I am relatively new to matlab and im trying to use Uelers formula to calculate pi. i am trying to save each term. I am unsure how to do this and spent a long time already trying to figure it out.
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Antworten (2)
the cyclist
am 24 Feb. 2020
Bearbeitet: the cyclist
am 24 Feb. 2020
clear
n = input('Number of terms: ');
terms = zeros(n,1);
for ni = 1:n
terms(ni)=terms(ni) + (sum(1/(ni^2)));
end
pi1=sqrt(6*terms);
fprintf('the estimate for pi is %g.\n',pi1);
errorF = ((pi1-pi)/pi)*100;
fprintf('the percentage error is %g.\n',errorF);
I did a few things here. The main one is that I made your variable terms into a vector, instead of a scalar.
Then, in each iteration of the loop, I write into one element of the vector, rather than overwriting the scalar over and over. (Note that I preallocated the memory for terms.)
Another small thing I did was change your looping variable to ni. It's confusing to have your looping variable named the same as an already existing variable in the workspace. What if you had wanted to refer to both?
0 Kommentare
Giuseppe Inghilterra
am 24 Feb. 2020
Hi,
try to run this code. I add a plot in which I show how "pi1" converges toward to pi value.
clear
n = input('Number of terms: ');
terms = zeros(n,1);
for ii = 2:n
terms(ii,1) = terms(ii-1,1) + 1/(ii-1)^2;
end
pi1=sqrt(6*terms);
plot(1:n,pi1,'-.')
hold on
plot(1:n, pi*ones(n,1))
fprintf('the estimate for pi is %g.\n',pi1(end));
errorF = ((pi1(end)-pi)/pi)*100;
fprintf('the percentage error is %g.\n',errorF);
I did some changes:
- terms is a vector, not a scalar;
- ii is loop variable, instead of n;
- add plot functions.
- (sum(1/(n^2))) becomes 1/(ii-1)^2 because n is a scalar not a vector, you don't need sum function.
You can add title, xlabel, ylabel to plot in order to make it more attractive.
2 Kommentare
Lourval
am 3 Feb. 2024
Hello Giuseppe! How could I do that if i have an expression with two variables, k and t, such as:
f(t)=(cos((2*k+1)*pi*t)/(2*k+1)^2 , t from 0 to m and k from 0 to n
and the objective is to plot f(t)
Lourval
am 6 Feb. 2024
Well, by trial and error i have found the solution:
clear
m = input('Number of tterms: ');
n = input('Number of kterms: ');
tterms = zeros(m,1);
kterms = zeros(n,1);
for t = 2:m
for k = 2:n
kterms(k,1)=kterms(k-1,1)+(cos((2*(k-2)+1)*(99/3240)*pi*t))/(2*(k-2)+1)^2;
end
tterms(t,1)=tterms(t,1)+kterms(k,1);
end
ang=90-720/(pi^2)*tterms
plot(1:n,ang,'-.')
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