Greatest Common Divisor, Recursive code

Hello,
This code uses recursion to find the GCD of two numbers that are inputed. The code works but for some reason GCD is being assigned to 0 at the end. The test case I am using sets greatestCommonDivisor(10007,500).
Any help is greatly appreciated
The code is as follows:
function GCD = greatestCommonDivisor(a, b)
if(a > b)
temp1 = a;
temp2 = b;
else
temp1 = b;
temp2 = a;
end
if temp1 == 0
GCD = temp2;
return
elseif temp2 == 0
GCD = temp1;
return
else
r = rem(temp1, temp2);
end
if(r == 0)
disp(temp2)
if(temp2 == 1)
GCD = 1;
disp(GCD)
return
else
GCD = temp2;
return
end
else
greatestCommonDivisor(temp2, r);
end
end

1 Kommentar

Jalaj Gambhir
Jalaj Gambhir am 25 Feb. 2020
Hi,
I do not see where GCD is assigned to 0, can you provide more clarifications/ output screenshot or something? Works fine for me, with GCD = 1 at the end.

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Antworten (1)

Deepak
Deepak am 21 Aug. 2024

0 Stimmen

Hi @Kitt Naughton, To my understanding, you have written code to calculate GCD of two integers.
Your code works fine, but the GCD variable is being assigned to 0 at the end.
To resolve this issue, when calling the recursive method “greatestCommonDivisor(temp2, r)” at the end, you need to assign the return value to the output variable GCD.
GCD = greatestCommonDivisor(temp2, r);
It is important to assign the result of a recursive call to a variable so that the result can be returned up the call stack.
By assigning “GCD = greatestCommonDivisor(b, r)” you capture this result and ensure it is returned correctly.
Here is the updated MATLAB code:
function GCD = greatestCommonDivisor(a, b)
if(a > b)
temp1 = a;
temp2 = b;
else
temp1 = b;
temp2 = a;
end
if temp1 == 0
GCD = temp2;
return
elseif temp2 == 0
GCD = temp1;
return
else
r = rem(temp1, temp2);
end
if(r == 0)
disp(temp2)
if(temp2 == 1)
GCD = 1;
disp(GCD)
return
else
GCD = temp2;
return
end
else
GCD = greatestCommonDivisor(temp2, r);
disp(GCD);
end
end
I hope this helps.

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Gefragt:

am 22 Feb. 2020

Bearbeitet:

am 21 Aug. 2024

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