Calling a function inside another function with iteration
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Jose Sosa Lopez
am 17 Feb. 2020
Bearbeitet: Jose Sosa Lopez
am 18 Feb. 2020
Hello community,
I am trying to reproduce a graph, but I guess I have a problem calling a function. Could you help me?
clear all; clc; close all;
c=1;
Yi0=c;
t=linspace(0,10,101);
T=0.1;
k=4;
for ite=2:101
y(ite)=funcion(T,t(ite),Yi(ite-1),k); %(Maybe here I have an error?)
end
plot(t,y')
%%
function Yout=funcion(T,t,Yi0,k)
Yi=zeros(k,1);
Yi(1)=Yi0;
for itek=2:k
for n=1:(k-1)
Yi(itek)=(T/(itek-1))*(Yi(itek-1)-exp(t(ite))*(Yi(n)*Yi(itek-n)));
Yi(itek)=Yi(itek)+Yi(itek-1); %I want to use in my next iteration, for Yi(1)= to the sum of the previous Yi(itek), so I dont know how o put it
end
end
Yout=sum(Yi);
end
the graph should be like this:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/272233/image.png)
3 Kommentare
Giuseppe Inghilterra
am 17 Feb. 2020
Hi,
in your code there are several errors. Example in following line:
y(ite)=funcion(T,t(ite),Yi(ite-1),k); %(Maybe here I have an error?)
you don't initialize Yi before, thus matlab returns an error.
In following line
Yi(itek)=(T/(itek-1))*(Yi(itek-1)-exp(t(ite))*(Yi(n)*Yi(itek-n)));
when you evaluate exp(t(ite)), the variable "ite" is not defined inside function. Maybe it should be "itek" instead.
In general I advice you to choose more appropriate name variables, in this way you are less error prone.
I finish to run code after these two errors.
Do you have mathematical formulation of the curve that you want to plot? It will be easier check your code.
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