how to find out distance between two points.
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
I have 8*2 matrix of numbers like
2 1
3 2
4 3
5 2
6 2
7 3
8 3
9 8
and another matrix of coordinates for these numbers like
1 19.75303200 0.43557600 2.65388300
2 0.77047300 0.06860900 2.48736300
3 1.50647300 19.88576300 3.80387500
4 2.93388400 19.40857700 3.52875700
5 1.29467400 0.79392000 1.85730000
6 0.70911200 19.12320300 1.93804200
7 1.57899700 0.85145000 4.31768200
8 0.80276600 18.88574500 4.70559200
9 0.74693100 17.90090500 4.22987600
now I have to find out the distace between points from column 1 to 2 of first marix using the coordinates from 2nd matrix. how can i do it?
1 Kommentar
Antworten (1)
Luna
am 11 Feb. 2020
Bearbeitet: Luna
am 11 Feb. 2020
Here you can use this:
NodeNumbersMatrix = [...
2 1
3 2
4 3
5 2
6 2
7 3
8 3
9 8 ...
];
CoordinatesMatrix = [...
1 19.75303200 0.43557600 2.65388300
2 0.77047300 0.06860900 2.48736300
3 1.50647300 19.88576300 3.80387500
4 2.93388400 19.40857700 3.52875700
5 1.29467400 0.79392000 1.85730000
6 0.70911200 19.12320300 1.93804200
7 1.57899700 0.85145000 4.31768200
8 0.80276600 18.88574500 4.70559200
9 0.74693100 17.90090500 4.2298760 ...
];
distance_array = nan(size(NodeNumbersMatrix,1),1); % preallocate
for i = 1:size(NodeNumbersMatrix,1)
points_to_look_between = NodeNumbersMatrix(i,:);
two_vectors_of_points = CoordinatesMatrix(points_to_look_between,2:end);
distance_of_two_vectors = sqrt(sum((two_vectors_of_points(1,:) - two_vectors_of_points(2,:)).^2));
distance_array(i) = distance_of_two_vectors;
end
%% OR
% shorter way for loop
for i = 1:size(NodeNumbersMatrix,1)
two_vectors_of_points = CoordinatesMatrix( NodeNumbersMatrix(i,:),2:end);
distance_array(i) = sqrt(sum((two_vectors_of_points(1,:) - two_vectors_of_points(2,:)).^2));
end
0 Kommentare
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!