For Loop for Non-Consecutive Values in an Array...
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Michelle De Luna
am 7 Feb. 2020
Kommentiert: Michelle De Luna
am 7 Feb. 2020
Hi everyone! I had a question regarding for loops when your "i" values are not consecutive.
I have a large matrix with thousands of timesteps. From this matrix, I need to find those index values where the date includes a specific month like December. I have been able to create a variable that includes the index value of all of those specifically selected timesteps quite easily, however the next step of my code includes a for loop where I use these index value to produce an image.
So, for example, my variable "December" is an array with timestep values like: 1745, 1767, 2918, 3958, 5938, and thousands more in random order.
How do I create a for loop that uses the specific timestep value (e.g. 1745 or 2918)? Would the "length" option do the trick? Any help would be greatly appreciated.
dec = find(dates.Month == 12)
for i = 1:length(dec)
i
end
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Walter Roberson
am 7 Feb. 2020
for i = dec
disp([i,dates(i).Month])
end
This might be enough for your situation. However, it is very common to need to have one output for each non-consecutive input. In such a case, you should learn this kind of pattern:
decvals = find etc
numdec = length(decvals);
outputs = zeros(numdec, 1);
for decidx = 1 : numdec
dec = decvals(decidx);
do something with dec
outputs(decidx) = whatever;
end
In this kind of pattern, decvals does not need to be consecutive or integer or unique -- it does not even need to be real-valued or numeric. This kind of pattern will loop through all of whatever values are there, extracting one at a time (here into the variable dec) and storing the output computed into the location corresponding to the offset into the array of values.
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