For Loop /Array question

1 Ansicht (letzte 30 Tage)
Tyler Young
Tyler Young am 3 Feb. 2020
Kommentiert: Tyler Young am 4 Feb. 2020
How would i go about creating a for loop to create an array where each value in X is equal to its associated row value * 2 plus its associated column value * 3 +1. Size of array is 50x50 ?
  2 Kommentare
James Tursa
James Tursa am 3 Feb. 2020
What have you done so far? What specific problems are you having with your code? Do you know how to write a for-loop? Do you know how to pre-allocate a 50x50 matrix?
Tyler Young
Tyler Young am 4 Feb. 2020
I know how to write simpler for loops where I can identify a "start" point for my indx and run through a simple array or vector to "end" but Im struggling to comprehend how to build the value of this equation.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Hiro Yoshino
Hiro Yoshino am 4 Feb. 2020
How about this?:
X = zeros(50, 50);
[m, n] = size(X); % m x n = 50, 50
for i = 1:m % Row
for j = 1:n % Column
X(i, j) = i * 2 + j * 3 + 1;
end
end
(m, n) could be anytihng.
The point here is size function. Good luck!
  1 Kommentar
Tyler Young
Tyler Young am 4 Feb. 2020
Thank you, that does work, and helps to see it done that way too. I ended up going about it differently, but I was orginally thinking of using "zeros"
for row = 1:1:50
for col = 1:1:50
X(row,col) = [row * 2 + col * 3 + 1]
end
end

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

KSSV
KSSV am 4 Feb. 2020
Check the below deom code where each element of a matrix is sum of its row and column position. Extend this to your case.
m = 5 ; % number of rows
n = 5 ; % number of columns
iwant = zeros(m,n) ; % initialize the required matrix
% loop
for i = 1:m % loop for row
for j = 1:n % loop for column
iwant(i,j) = i+j ; %(i,j)th element is sum of i and j
end
end
  1 Kommentar
Tyler Young
Tyler Young am 4 Feb. 2020
Thank you, appreciate the multiple ways of seeing this done.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by