Is it possible to vary 5 variables in an equation using linspace and plot 3 of them using contour?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
I have an equation of a physical system and I want to vary 5 parameters (i, N, r1, r2 and L) using linspace or :. My aim to find that an optimum configuration (i.e. a set of values of these variables) that gives me the maximum value of field. However, I get an empty plot when I run this code and I also get an error saying "Undefined function or variable 'field'."
Moreover, I get the values of t =r2-r1 as zero for all values in the workspace.
I would really appreacite if someone could kindly help me.
Thank you in advance.
uo = 1.26*(10^-3);
L=linspace(1,70);
N=linspace(100,1000,10);
i=linspace(1,5,10);
r1=linspace(1,50,100);
r2=linspace(1,50,100);
x1= 10;
x2= x1+L;
t=r2-r1;
[L,t] = meshgrid(L,t);
if r2>r1
g=sqrt((r2.^2)+(x2.^2));
m=sqrt((r1.^2)+(x2.^2));
n=sqrt((r2.^2)+(x1.^2));
o=sqrt((r1.^2)+(x1.^2));
A = reallog((g+r2)./(m+r1));
B = reallog((n+r2)./(o+r1));
field = ((uo.*N.*i)./(2.*L*(r2-r1))).*((x2.*A)-(x1.*B));
end
figure
contour(L,t,field)
1 Kommentar
Walter Roberson
am 2 Feb. 2020
field is not defined unless r2>r1 . However,
r1=linspace(1,50,100);
r2=linspace(1,50,100);
so they are both vectors of the same size and same content, so r2 > r1 is never true because r2 == r1
Antworten (1)
Walter Roberson
am 2 Feb. 2020
Bearbeitet: Walter Roberson
am 2 Feb. 2020
uo = 1.26*(10^-3);
Lvec = linspace(1,70);
Nvec = linspace(100,1000,10);
ivec = linspace(1,5,10);
r1vec = linspace(1,50,100);
r2vec = linspace(1,50,100);
[L, N, i, r1, r2] = ndgrid(Lvec, NVec, ivec, r1vec, r2vec);
x1= 10;
x2= x1+L;
t=r2-r1;
Z = zeros(size(r2));
field = Z;
mask = r2 > r1;
g = sqrt((r2(mask).^2)+(x2(mask).^2));
m = sqrt((r1(mask).^2)+(x2(mask).^2));
n = sqrt((r2(mask).^2)+(x1(mask).^2));
o = sqrt((r1(mask).^2)+(x1(mask).^2));
A = reallog((g+r2(mask))./(m+r1(mask)));
B = reallog((n+r2(mask)./(o+r1(mask))));
field = ((uo.*N(mask).*i(mask))./(2.*L(mask)*(r2(mask)-r1(mask)))).*((x2(mask).*A)-(x1(mask).*B));
[maxfield, maxixd] = max(field);
LNir1r2 = [L(maxid), N(maxid), i(maxid), r1(maxid), r1(maxid)]; %parameter values at maximum
However, do not try to contour field: it is a 5 dimensional variable. You can do things like a "maximum projection" over a 2D subset of the values:
p134 = squeeze(max(field, [], [1 3 4]));
contour(Nvec, r2vec.', p134);
0 Kommentare
Siehe auch
Kategorien
Mehr zu Matrices and Arrays finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!