Create .m file programmatically with fitting metadata

Hi@all,

I'm trying to build a unit test generator, but I dstruggle a little bit :/

planned steps:

1. Find the file to create the test for (input is filename)
2. Check if test folder exist or create them (based on package name)
3. copy and rename a prepared template file
4. rename the file name in the content
5. add all public methods as test methods with special naming and prefilled content
6. finsh

My problem is at the moment, if I change the content by using sth like this:

function renameFileNameContent(testPath, testName)
    [~, name, ~] = fileparts(fullfile(testPath, testName));
    fid = fopen(fullfile(testPath, testName), 'r');
    fileContent = rot90(StringConverter.ensureCharString(fread(fid, '*char')));
    fclose(fid);
    fileContent = regexprep(char(fileContent), testing.UnitTestSupport.TemplateName, name);
    fid = fopen(fullfile(testPath, testName), 'w');
    fprintf(fid, '%s', fileContent);
    fclose(fid);
end

The problem here is it's seems that the .m has meta data which are emtpy after this file recreation ...

My second try was sth like this:

function renameFileNameContent(testPath, testName)            
    fid = fopen(fullfile(testPath, testName), 'r');
    fileContent = rot90(StringConverter.ensureCharString(fread(fid, '*char')));
    fclose(fid);
    
    fileContent = regexprep(char(fileContent), testing.UnitTestSupport.TemplateName, name);

    editorService = com.mathworks.mlservices.MLEditorServices;
    editorApplication = editorService.getEditorApplication();
    editorApplication.newEditor(fileContent);
    openFiles = matlab.desktop.editor.getAll();
    
    %save(fullfile(testPath, testName), openFiles(length(openFiles)).Filename);
end

Now I have the file open as new untiteled file and can save it, but still the same issue :/

Did someone solved this problem, or can give me a hint to handle this?

Best regards

Answer 1

[Ricardo Krause]

ok, found the solution ...

the file was in a package folder stored and needs to be called by package.Filename