calculating mean values of a 3D matrix
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noa
am 9 Okt. 2012
Kommentiert: ankit patel
am 11 Apr. 2020
hi.
I have a 3D matrix. size 79x63x100
I want to calc the mean of each of the 79x63 values so to get a 2D matrix the size of 79x63x1
but when i do mean(mat) i get it in the size of 1x63x100
how should I write it?
Thanks, Noa
2 Kommentare
Deepak Singh
am 15 Jul. 2015
You can mention the dimension you want to take mean across. Something like this will work: x=mean(mat,3);
ankit patel
am 11 Apr. 2020
its not working if i change the value 3 with more than 3 in your equation.
Akzeptierte Antwort
Andrei Bobrov
am 9 Okt. 2012
out = mean(yourarray3D,3)
5 Kommentare
Akshay Bhardwaj
am 24 Mai 2018
Bearbeitet: Akshay Bhardwaj
am 24 Mai 2018
out = std(yourarray3d,[],3)
BBB
am 13 Nov. 2019
Hi,
I also have a similar question.
I have a 51x51 2D matrix that I need to take a mean off, but it has to give me back a 51x51 2D matrix as an output.
How can do this using the mean function. I need to put this in a loop as well. Please see code below for reference:
rand_image_stim = rand(10000,51,51);
kk = 1:length(rand_image_stim);
firing_rate_kk(kk) = 0;
gab_filt = z_cos.*z_gauss;
lp(kk) = 0;
for kk = 1:length(rand_image_stim)
output_kk = squeeze(rand_image_stim(kk,:,:)).*gab_filt;
firing_rate_kk(kk) = sum(output_kk,'all');
jk = squeeze(rand_image_stim(kk,:,:))*firing_rate_kk(kk);
lp = squeeze(mean(jk,2)); %Need help with this last bit!
end
Weitere Antworten (1)
Zoe
am 28 Nov. 2017
shape2 = reshape(yourarray,[100 79*64]);
meanArray = mean(shape2,2);
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