How to a create for loop for this ?
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data2 = data1(1:25,:);
Cc = cov(data2);
data3 = data1(26:51,:);
Cc1 = cov(data3);
data4 = data1(52:77,:);
Cc2 = cov(data4);
1 Kommentar
Guillaume
am 28 Jan. 2020
Bearbeitet: Guillaume
am 28 Jan. 2020
Shouldn't the indices be 26:50 and 51:75 to be consistent with the 25 rows of the 1st calculation? How many rows does your data1 matrix has?
While it's easy to write a loop, you can even do this without a loop in just one line, as long as the step is consistent and the height of the matrix is a multiple of the step.
Antworten (3)
Paresh yeole
am 28 Jan. 2020
Bearbeitet: Paresh yeole
am 28 Jan. 2020
There is inconsistency. The first covariance value is for 25 numbers and the other two are for 26 numbers. If you are looking for 25 no. sets then following loop would do.
for i =1:3
Cc(i) = cov(data(1+(i-1)*25 : 25*i,: ));
end
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