# loop to work with the column

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Lev Mihailov on 27 Jan 2020
Edited: Lev Mihailov on 27 Jan 2020
Hello! There is a loop, I need to know automatically how many values ​​after the point
X=[1 2 3 4 5 6 90 70 60 50 6 5 4 3 2
1 2 3 4 5 6 60 70 60 50 6 5 4 3 2
1 2 3 4 5 6 60 60 70 50 6 5 4 3 2]';
for i=1:length(X(1,:))
[~,loc1]=max(X);
end
% and now I need to find out how many values ​​from maxim to 6
% ans(1) = 4 % 70 60 50 6 % ans(2)=3 % 60 50 6 % ans(3)=2
how do i do this?
##### 2 CommentsShowHide 1 older comment
Lev Mihailov on 27 Jan 2020
point of my maximum, the values should be from it to 6 (or close to this value 5.9.6.1)
p.s.the loop should get the same answers as mine
X=[1 2 3 4 5 6 90 70 60 50 6 5 4 3 2
1 2 3 4 5 6 60 70 60 50 6 5 4 3 2
1 2 3 4 5 6 60 60 70 50 6 5 4 3 2]';
% ans(1)=4; ans(2)=3; ans(3)=2

KSSV on 27 Jan 2020
iwant = sum(X>6,1)
Lev Mihailov on 27 Jan 2020
iwant =
4 4 4
such a variation gives the wrong answer

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