can't get all the other characters = 26

Write a function m-file called stringcode that takes a string as input and produces an array containing a code for each letter in the string with A = 0, B = 1, ..., Z = 25 and all other characters getting the value 26.

function num = stringcode( word )

asc= double((word))

if asc >= 33 & asc <=47

asc = 26

else asc= double(upper(word))

end

asc= double(upper(word))

num = asc - double('A'); % simple arithmetic

end

[James Tursa]

asc is a vector, but your code treats it as a scalar. You either need to wrap your code in a loop to do each character one at a time, or you need to vectorize your code.

[Benjamin Trivers]

explain a little bit more?

Answer 1

[Image Analyst]

You don't need all that complicated stuff. You almost had it at the end, so simply subtract 'A' and you're done. None of that foregoing stuff is needed. Watch:

>> num = 'ABCDEFGHIJKLMNOP' - 'A'

num =

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

[Benjamin Trivers]

I still don't follow. Where does the num= go into?

[Image Analyst]

In your function of course:

function num = stringcode( word )
num = word - 'A'
num(num<0 | num>25) = 26;

Just throw out all that useless stuff you had and have just those three lines. Basically the same as what you have except you don't need to cast to double