Error using integral function
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Yashika
am 14 Jan. 2020
Kommentiert: Star Strider
am 14 Jan. 2020
Dear MATLAB users,
I am using integral function in which I am getting error. I read the questions others asked. The answers says we should add .* instead of * where two terms are getting multiplied. Kindly help to solve it as the function I am solving in "integral function" is autogenerated by some other function.
My code is as follows:
syms x y
alpha = 45*pi/180;
b = cos(alpha);
l = 0;
N = 10;
phi = 0;
X = (sqrt(1-x*x)/sin(alpha))*cos(phi);
Y = (sqrt(1-x*x)/sin(alpha))*sin(phi);
Z = (x-cos(alpha))/sin(alpha);
r = sqrt(X*X+Y*Y+Z*Z);
y1 = x;
y2 = (x/2)*log((1+x)/(1-x)) - 1;
for i=1:N
for j=1:N
fun = y1.*int(subs(y2.*r^j,x,y).*ALP(j,l,y),y,x,1)
G0j = integral(@(x)fun,b,1)
end
end
function y = ALP(j,l,x)
y = ((-1)^l)*(1-x*x)^(l/2)*diff(legendreP(j,x),l);
end
Error is as follows:
Error using integralCalc/finalInputChecks (line 522)
Input function must return 'double' or 'single' values. Found 'sym'.
Error in integralCalc/iterateScalarValued (line 315)
finalInputChecks(x,fx);
Error in integralCalc/vadapt (line 132)
[q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 75)
[q,errbnd] = vadapt(@AtoBInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in rough (line 66)
G0j = integral(@(x)fun,b,1)
One more question:
I was initially using symbolic integration. But as I increase number of terms in expansion MATLAB didn't solve it but return expression as int(fun,Xmin,Xmax). Is there any way to resolve this. Can matlab solve complecated symbolic algebra?
Thank You.
Yashika
0 Kommentare
Akzeptierte Antwort
Star Strider
am 14 Jan. 2020
Try this instead:
ALP = @(j,l,x) ((-1)^l)*(1-x*x)^(l/2)*diff(legendreP(j,x),l);
syms x y
alpha = 45*pi/180;
b = cos(alpha);
l = 0;
N = 10;
phi = 0;
X = (sqrt(1-x*x)/sin(alpha))*cos(phi);
Y = (sqrt(1-x*x)/sin(alpha))*sin(phi);
Z = (x-cos(alpha))/sin(alpha);
r = sqrt(X*X+Y*Y+Z*Z);
y1 = x;
y2 = (x/2)*log((1+x)/(1-x)) - 1;
for i=1:N
for j=1:N
fun = y1.*int(subs(y2.*r^j,x,y).*ALP(j,l,y),y,x,1);
G0(i,j) = vpaintegral(fun,x,b,1)
end
end
The integral function will not work with symbolic variables or symbolic functions. The vpaintegral function (R2016b and later releases) will. Use the double function with ‘G0’ to convert it to a double array (with some loss of precision) if you want to use it in non-symbolic calculations.
2 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Calculus finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!