Create subfolders in the desired way
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Daphne PARLIARI
am 14 Jan. 2020
Kommentiert: Daphne PARLIARI
am 14 Jan. 2020
Hi community! I would appreciate your contribution to the following.
I have created the directory I want (the first of which is C:\Users\dparliari\Desktop\OutputEv\Airport\Temperature) using the following lines:
output_path='C:\Users\dparliari\Desktop\OutputEv'
vars={'Temperature'; 'Relative humidity'};
for m=1:size(vars,1)
if(~exist([output_path,'\',namestr,'\',strrep(vars{m},' ','_'),'\'],'dir'))
mkdir([output_path,'\',namestr,'\',strrep(vars{m},' ','_'),'\'],'dir')
end
end
Now I want to create a subfolder based on the year in this way: C:\Users\dparliari\Desktop\OutputEv\Airport\Temperature\2015
I guess it must be something like:
output_path='C:\Users\dparliari\Desktop\OutputEv'
vars={'Temperature'; 'Relative humidity'};
years = {'2015'; '2019'};
for m=1:size(vars,1)
if(~exist([output_path,'\',namestr,'\',strrep(vars{m},' ','_'),'\'],'dir'))
mkdir([output_path,'\',namestr,'\',strrep(vars{m},' ','_'),'\'],'dir')
for k = 1:size(years,1)
if(~exist([I HAVE NO IDEA!!))
mkdir([ALSO NO IDEA!!)
end
end
end
Any ideas please??
2 Kommentare
Akzeptierte Antwort
Guillaume
am 14 Jan. 2020
Bearbeitet: Guillaume
am 14 Jan. 2020
As Per isakson said, use fullfile instead of building paths manually. fullfile automatically inserts the correct path separator for whichever OS your code is running on.
I would do it like this
output_path='C:\Users\dparliari\Desktop\OutputEv';
vars={'Temperature'; 'Relative humidity'};
years = {'2015'; '2019'};
[vv, yy] = ndgrid(vars, years); %note that this syntax is not officially supported. If it's a problem use
%[vv, yy] = ndgrid(1:numel(vars), 1:numel(years)); vv = vars(vv); yy = years(yy);
allfolders = fullfile(output_path, 'Airport', vv, yy);
for fidx = 1:numel(allfolders)
if ~exist(allfolders{fidx}, 'dir')
mkdir(allfolders{fidx});
end
end
3 Kommentare
Guillaume
am 14 Jan. 2020
First, you need to learn to use tables properly.
stations(x, y)
uses () indexing and thus returns a table (the portion of the table referenced by indices x, y.
stations{x, y}
uses {} indexing and thus returns the content of the table.
Another way to get the content is with . indexing:
stations.y(x)
So, instead of:
network = stations (i, 'Network');
% ...
networkstr = char(network.(1));
simply:
networkstr = char(stations{i, 'Network'});
or
networkstr = char(stations.Network(i)); %probably simpler
I'm not convinced the char() conversion is even needed.
So I can understand better what your code is doing, can you attach an example input table?
Weitere Antworten (1)
per isakson
am 14 Jan. 2020
Bearbeitet: per isakson
am 14 Jan. 2020
Try this
%%
output_path = 'd:\m\cssm'; % 'C:\Users\dparliari\Desktop\OutputEv'
vars = {'Temperature', 'Relative_humidity'};
years = {'2015', '2019'};
for vv = vars
for yy = years
ffs = fullfile( output_path, 'Airport', vv{:}, yy{:} );
mkdir( ffs );
end
end
1 Kommentar
Siehe auch
Kategorien
Mehr zu File Operations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!