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Matrix dimension must agree

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Saskia Nur Santika
Saskia Nur Santika am 9 Jan. 2020
Ihave a code
xd=-(sqrt(R²-ho²)):0.5:x3;
xd1=x3;
yd1=y3;
xd2=-(sqrt(R²-ho²));
yd2=ho;
yd=(((xd-xd1)./(xd2-xd1)).*(yd2-yd1))+(yd1);
plot(xd,yd,'k')
The result is:
Eror using .* Matrix dimensions must agree.
Please help mee ?
*code formatted by Adam Danz; the squared superscripts are ambiguous (^2 or .^2) so I left them as-is - AD
  3 Kommentare
David Hill
David Hill am 9 Jan. 2020
You need to provide more information. Look at the size of each of your matrixes. If you want help you will need to provide examples of your variables.
Saskia Nur Santika
Saskia Nur Santika am 9 Jan. 2020
f=15; R=2*f; ho=12; so=10; sia=-((f*so)/(f+so)) x3=-r-sia

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Akzeptierte Antwort

Adam Danz
Adam Danz am 9 Jan. 2020
In this line
yd = (((xd-xd1)./(xd2-xd1)).*(yd2-yd1))+(yd1);
% ^^
The terms to the left and right of .* are not the same size. The dot-asterisk notation specifies element-wise multiplication where x .* y is interpretted as x(i) * y(i). That requires that x and y are the same size.
The two lines below must produce the same output.
size(((xd-xd1)./(xd2-xd1)))
size((yd2-yd1))
  2 Kommentare
Saskia Nur Santika
Saskia Nur Santika am 9 Jan. 2020
Thankyouu
KALYAN ACHARJYA
KALYAN ACHARJYA am 9 Jan. 2020
If your question is answered, you can accept the answer.

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Weitere Antworten (1)

Mateus Banroc
Mateus Banroc am 9 Jan. 2020
Hi Saskia,
In your code, I guess that only xd and yd are vectors, right? So x3, y3, R and ho should be scalars.
I don't know what are the values of these scalars but I tried this and it worked.
R=10; ho=2;
x3=10;
y3=10;
xd=-(sqrt(R^2-ho^2)):0.5:x3;
xd1=x3;
yd1=y3;
xd2=-(sqrt(R^2-ho^2));
yd2=ho;
yd=(((xd-xd1)./(xd2-xd1)).*(yd2-yd1))+(yd1);
plot(xd,yd,'k')
You must check if R, ho, x3, y3 are scalars.

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