bisection method - can't see error in code

1 Ansicht (letzte 30 Tage)
Christie
Christie am 3 Okt. 2012
I am unable to pin point the error in my code of my funtion for the bisection method, any help would be greatly appreciated
function [rootx]=bisect(fhandle,a,b,epsilon)
rootx=[];
Fa=fhandle(a);
Fb=fhandle(b);
m=((b-a)/2);
Fm=fhandle(m);
while abs(m)>epsilon ;
if Fb*Fm <0
a=m
else
b=m
end
end
return m=((a+b)/2)
end
rootx
  2 Kommentare
Matt J
Matt J am 3 Okt. 2012
Bearbeitet: Matt J am 3 Okt. 2012
Not pasting in the error messages or other symptoms of malfunction makes it hard for us to pinpoint, too.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

James Tursa
James Tursa am 3 Okt. 2012
1) Google "bisection method"
2) Go to the 1st Wiki link
3) Look at the pseudo-code posted there
4) Compare that to your code to discover your errors, paying special attention to what Matt J said about not updating your variables within your loop.

Weitere Antworten (2)

Matt J
Matt J am 3 Okt. 2012
Bearbeitet: Matt J am 3 Okt. 2012
One idea:
m=((b-a)/2);
Shouldn't it be + instead of - ?
Also, you don't assign anything to rootx in the code except the initialization rootx=[]. Also, throughout the loop, you are not updating, m, Fb, or Fm.

Babak
Babak am 3 Okt. 2012
In the while loop
while abs(m)>epsilon ;
if Fb*Fm <0
a=m
else
b=m
end
end
you are not changing m and you are trying to check the abs(m)
I think you meant
m=a
and
m=b
instead...

Kategorien

Mehr zu Programming finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by