# Unable to perform assignment because the left and right sides have a different number of elements error

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Wendelin Potz on 10 Dec 2019
Edited: Matt J on 10 Dec 2019
when running this algorithm i get the following error "
Error in Grammel (line 36)
t1(i) = ot(i) + b*(w^2)*(r(i).^2);
>> Grammel
Unable to perform assignment because the left and right sides have a
different number of elements."
it seems to me as if t1(i) is the i-th element of a 1*6 integer matrix, which is defined as ot(i) (the ith element of another integer 1*6 matrix)+ (someconstant)*r(i) (yet another ith elementof an 1*6 integer matrix).
i dont see what the issue is here or why the integer value of t1(i) shouldn´t have the same dimensions as the two other integer values added together.
p = 1;
u = 0.31;
a = ((3+u)/8)*p;
b = ((1+3*u)/8)*p;
f = 14897/60;
w =2*pi*f;
%TEILSCHEIBE 1
or = [15.8e+7,0,0,0,0,0];
ot= [2.3778e+11,0,0,0,0,0];
%orinnen = [1,0,0,0,0,0];
%otinnen= [1,0,0,0,0,0];
r = [56,112,168,224,280,325];
%rinnen = [1,2,3,4,5,6];
b = [45,30,40,50,60,70]; %breite der iten Teilscheibe
db =[15,10,10,10,10,10]; %aenderung Teilscheibentiefe von i zu i+1
A = [0,0,0,0,0,0]; %Flächeninhalt ringscheibe
s1 = [0,0,0,0,0,0];
t1 = [0,0,0,0,0,0];
ss = [0,0,0,0,0,0];
ts = [0,0,0,0,0,0];
do = [0,0,0,0,0,0];
dt =[0,0,0,0,0,0];%delta t
for i = 1:6
s1(i) = or(i) + a*(w^2)*(r(i).^2);
t1(i) = ot(i) + b*(w^2)*(r(i).^2);
K1i = (si1+ti1)/2;
K2i = (si1-ti1)/(2/(r(i)^2));
si2 = K1i + K2i/(r(i+1)^2);
ti2 = K1i - K2i/(r(i+1)^2);
or(i+1) = si2 -a*(w^2)*(r(i+1)^2)
ot(i+1) = ti2 -a*(w^2)*(r(i+1)^2)
dsi = (-db(i)/(b(i)+db(i)))*or(i+1);
dti = u *dsi;
ss(i) = si2 + dsi;
ts(i) = ti2 + dti;
s1(i+1) = ss(i);
t1(i+1) = ts(i);
do(i) = ot(i)+ot(i+1);
A(i) = pi* ((r(i)^2)-(r(i+1)^2));
doA(i) = do(i).*A(i);
end
otm = sum(doA)/(2*sum(A))
bm = (otm*1.5)/1400