Solve Integral Equation with function handles

Hey everyone!
I am facing a problem. I want to get at the end a value for the variable flux.
dpsi = -5;
etaK = 2;
etaL = 4;
j0 = 1;
UT = 1;
syms flux
Fermi =@(eta) sqrt(pi)./ (2 .* (3/4 .* sqrt(pi) .*( eta.^4 + 33.6.*eta *(1.0-0.68.*exp(-0.17*(eta+1).^2) ) + 50).^(-3/8) + exp(-eta) ));
InnerInt = @(eta, flux) 1/ ( flux/Fermi(eta) + dpsi/UT);
integralEq = @(flux) integral( @(eta) InnerInt(eta, flux), etaK, etaL);
jKG = j0 * solve( integralEq(flux) == 1);
Can someone please help me?

 Akzeptierte Antwort

Star Strider
Star Strider am 8 Dez. 2019

1 Stimme

Every multiplication in ‘Fermi’ needs to be vectorised (with element-wise operations), the Symbolic Math Toolbox is not necessary, (so replace solve with fsolve), and use the ArrayValued name-value-pair in the integral call.
With those changes, your code:
dpsi = -5;
etaK = 2;
etaL = 4;
j0 = 1;
UT = 1;
Fermi = @(eta) sqrt(pi) ./ (2 .* (3/4 .* sqrt(pi) .*( eta.^4 + 33.6.*eta .* (1.0-0.68.*exp(-0.17*(eta+1).^2) ) + 50).^(-3/8) + exp(-eta) ));
InnerInt = @(eta, flux) 1/ ( flux/Fermi(eta) + dpsi/UT);
integralEq = @(flux) integral( @(eta) InnerInt(eta, flux), etaK, etaL, 'ArrayValued',1);
jKG = j0 * fsolve(@(x) integralEq(x) - 1, 10)
now produces this result:
jKG =
-3033.2578125

2 Kommentare

DA
DA am 8 Dez. 2019
Thank you very much for your quick response!
This solved the problem!
As always, my pleasure!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Mathematics and Optimization finden Sie in Hilfe-Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by