Why this algorithm produces a relative error?
Ältere Kommentare anzeigen
sum1=single(0); .
k=0;
sum=single(1);
while(sum==sum1)
sum=sum1;
k=k+1;
sum1=sum+single(1/k^2);
end
disp('expected result');
disp(pi^2/6); %1.6449
disp('your result:');
disp(somma); %1
disp('k:');
disp(k) %0
disp('RELATIVE ERROR: ');
disp(abs(somma-pi^2/6)/ (pi^2/6)); %0.3921
We works in finite arithmetic but I don't don't know the 'inner reason' of why this algorithm is so unstable. Thank you all.
Akzeptierte Antwort
Weitere Antworten (1)
Image Analyst
am 30 Nov. 2019
1 Stimme
Don't use sum as the name of your variable. It's the name of a built-in function that you don't want to destroy.
Kategorien
Mehr zu Performance and Memory finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!