Akzeptierte Antwort

JESUS DAVID ARIZA ROYETH
JESUS DAVID ARIZA ROYETH am 25 Nov. 2019

1 Stimme

directly:
n=100;
x=rand(1,n);
s=std(x)
or with a loop:
n=100;
x=rand(1,n);
xmean=mean(x);
sumt=0;
for i=1:n
sumt=sumt+(x(i)-xmean)^2;
end
s=sqrt(sumt/(n-1))

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