Unable to perform assignment because the indices on the left side are not compatible with the size of the right side - Jacobi method inverse calculation
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Kiana Bahrami
am 19 Nov. 2019
Kommentiert: Kiana Bahrami
am 19 Nov. 2019
Does anyone know why I'm getting this error: " Unable to perform assignment because the indices on the left side are not compatible with the size of the right side." I'm trying to perform a jacobi method inverse of my A matrix using identity matrix b. Thanks in advance!
A = [8 0 1 1 4; 2 9 1 4 0; 1 5 9 2 1; 1 1 4 12 1;2 3 1 4 16];
n = length(A);
b = eye(n);
%lambda = 1;
xinit = zeros(n,1);
norm = 2;
tol = 1.E-6;
maxiter = 100;
fprintf('\n-----Problem 1a------\n')
fprintf('The correct answer will be:')
[x,err,iter] = jacobi(A,b,xinit,tol,maxiter,norm);
x
err
iter
%% Function
% Jacobi
function [x,errst,iter] = jacobi(A,b,x,tol,maxiter,norm)
d = diag(A);
A = A - diag(d);
d = 1./d;
A = (A'*diag(d))';
b = b.*d;
err = 1.;
xold = x;
iter = 0;
while err>tol && iter<maxiter
iter = iter + 1;
x = b-A*x;
errst(iter,:) = errnorm(x-xold)./errnorm(x);
err = errst(iter,norm);
xold = x;
end
if iter>=maxiter
fprintf('\nLinear solver maxiter exceeded!!!\n')
end
end
function [abserr] =errnorm(vec)
vec = abs(vec);
abserr(1,1)= sum(vec);
abserr(1,2) = sqrt(vec'*vec);
abserr(1,3) = max(vec);
end
0 Kommentare
Akzeptierte Antwort
Erivelton Gualter
am 19 Nov. 2019
Function errnorm(vec) has inconsistent size. Try the following modifications:
function [abserr] =errnorm(vec)
vec = abs(vec);
abserr(1,1)= trace(vec);
abserr(1,2) = trace(sqrt(vec'*vec));
abserr(1,3) = max(max(vec));
end
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Characters and Strings finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!