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Hello,

I have a 3d array, precip= :,:, 8760. in fact 8760 rows are available in one column. I want to find the maximum value in this column 24-by-24 in rows. And saving the bigger value and eliminate the smaller one. and do it for all 8760-row

so if the dimension before doing this is precip = :, :, 8760, after this work should be precip = :, :, 365.

I wanna practical this for a 3d array which the third dimension is what I talking about.

I'm attaching all my array. as the volume of original file is so big I cut first 72 rows and attach it

Thank you

Shubham Gupta
on 14 Nov 2019

Edited: Shubham Gupta
on 14 Nov 2019

According to the comments, you have provided, this will produce the desired output :

yd = max(max(mn2t)); % first find maximum for each hour

y = reshape(yd,24,1,size(yd,3)/24); % reshape it by day

output = max(y); % find maximum of each day

Let me know if this works !

Shubham Gupta
on 14 Nov 2019

Simply use for loop mn2t:

output = cell(size(mn2t));

for i = 1:length(mn2t)

mn2t_mat = mn2t{i}; % extract matrix of ith element

yd = max(max(mn2t_mat)); % first find maximum for each hour

y = reshape(yd,24,1,size(yd,3)/24); % reshape it by day

output{i} = max(y); % find maximum of each day

end

Output will be cell vector with each cell containing maximum of each cell of mn2t.

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