Remove Entire Column when a condition is met.

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Pragyan Dahal
Pragyan Dahal am 30 Okt. 2019
Kommentiert: Pragyan Dahal am 30 Okt. 2019
Hello, I am constructing a cost matrix for an association problem. It is a minimization problem and the cost matrix is structured in this way
C=[12 inf 13 inf inf inf inf;
13 inf 15 inf inf inf inf;
inf inf inf 14 inf 27 inf]
The aim for me is to remove the column in which I have inf elements only i.e. in this example i want to remove 2nd, 5th and 7th column from the cost matrix.
Thanks in advance for the help.

Antworten (1)

pavan kumar
pavan kumar am 30 Okt. 2019
C(:,2)=[]
C(:,4)=[]
C(:,5)=[]
  2 Kommentare
Pragyan Dahal
Pragyan Dahal am 30 Okt. 2019
Thank you very much for the reply, this i figured given some answers for the row cases in this forum, but i am not sure on how to define the condition here, i mean, condition such that all the elements are infinite....
Pragyan Dahal
Pragyan Dahal am 30 Okt. 2019
I was able to solve the issue by using the code segment shown below.
remove=true(size(C,2),1);
for pp=1:size(C,2)
qq=1;
while C(qq,pp)==inf
qq=qq+1;
if qq==size(C,1)+1
remove(pp)=0;
break
end
end
end
C=C(:,remove)

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