Array Indices(dont understannd the problem the value is a basic exponantial function)
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
dont understannd the problem the value is a basic exponantial function
vds=1:0.1:5;
t=1.12;
idss=18;
x=vds/t;
ids=idss(1-exp((x)))
plot(vds,ids)
0 Kommentare
Antworten (1)
Steven Lord
am 18 Okt. 2019
idss is a variable with only one element. The expression idss(1-exp((x))) is an attempt to access one or more elements from that variable. The only valid index into idss is 1 (since it has only one element) and for 1-exp(x) to result in a value of 1, x must be -Inf (or something that causes exp(x) to underflow to 0.)
If you meant to multiply the variable idss and the value of the expression 1-exp(x), you need to specify the multiplication explicitly by putting .* between those two terms.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Data Type Conversion finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!