Precise Matrix Power: A^k
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Eric Schöneberg
am 14 Okt. 2019
Kommentiert: Eric Schöneberg
am 15 Okt. 2019
Hello,
I am currently fighting with (more than) double-precision numerics, with which I am not familiar, so the answer probably lies within this topic. I would like to calculate
with and but obviously the precision of will be bad for big k. Is there a datatype of which I am not aware, or any other trick that will help me? Thanks in advance. :)
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Rik
am 14 Okt. 2019
It will probably be helpfull to use the Symbolic Math Toolbox, and use the tips explained here. For mod(a^b,k) there is a direct function, but for your use case there doesn't seem to exist one.
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