Function to check if a number is divisible by 5

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hna
hna am 13 Okt. 2019
Bearbeitet: Walter Roberson am 30 Mär. 2023
How can I write a function m.file that takes as input a real number and checks to see if it is divisible by 5. An appropriate message indicating the result should be the output.
I have tried to write this but it dosen't seem to work as I need the user to input a number and check if it is divisble by 5
function [resp] = div5(x)
if (rem(x,5) == 0)
resp = 1;
else
resp = 0;
end
Thanks in advance
  4 Kommentare
Walter Roberson
Walter Roberson am 13 Okt. 2019
No you would use the code from before and then at the command line
div5(10)
Fahrizal Nurcahya
Fahrizal Nurcahya am 15 Okt. 2020
Bearbeitet: DGM am 30 Mär. 2023
bro it must be like this, check it my function
function [a] = div5(x)
% [x] = div5(x) - to checks a real number if it is divisible by 5.
for a=rem(x,5)
if a~=0
[a] ='NOT divisible by 5.';
else
[a] ='divisible by 5.';
end
end
end

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Antworten (1)

AKASH KUMAR
AKASH KUMAR am 29 Mär. 2023
Bearbeitet: DGM am 30 Mär. 2023
% check "a" is divisible by "b" or not
function test = divisibility_test(a,b)
if ceil(a/b)-a/b==0
test = true;
else
test=false;
end
end
  1 Kommentar
DGM
DGM am 30 Mär. 2023
The output of
ceil(a/b)-a/b==0
is a logical array, and the first conditional is only executed if every element of that array is true. So the whole thing simplifies to
function test = divisibility_test(a,b)
test = all(ceil(a/b)-a/b==0);
end
or just
function test = divisibility_test(a,b)
test = all(~mod(a,b));
end

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