Functional form of the colon (:) operator?

This is a post about "how to write neat, efficient, readable MATLAB code". I get the job done by doing work-arounds, but I would rather not do those.
Assume that a, b are two vectors of unknown orientation, and we want to compute something similar to the dot-product.
It might look something like this:
function y = myfunc(a,b)
//make sure that vectors are oriented the same way
y = a(:) .* b(:);
But what if I need to calculate y for elements 2:N? We might do something like this, but I think it clutters the code:
function y = myfunc(a,b)
a = a(2:end)
b = b(2:end)
y = a(:) .* b(:);
I am wishing for a functional form of the colon operator that might look something like this:
function y = myfunc(a,b)
y = colon(a(2:end)) .* colon(b(2:end));

 Akzeptierte Antwort

José-Luis
José-Luis am 18 Sep. 2012

2 Stimmen

function y = myfunc(a,b)
//make sure that vectors are oriented the same way
y = reshape(a(2:end),[],1) .* reshape(b(2:end),[],1);

1 Kommentar

Jan
Jan am 10 Okt. 2017
Nice, short, efficient: I have accepted this answer.

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Weitere Antworten (3)

Daniel Shub
Daniel Shub am 18 Sep. 2012

0 Stimmen

I thought that squeeze would do what you want, but apparently it doesn't "work" on row vectors. What would be nice is if squeeze had a row flag. Barring that, you can easily create your own colon function. From
type squeeze
it should be obvious what you need to change.
Royi Avital
Royi Avital am 10 Okt. 2017

0 Stimmen

I really wish MATLAB would add function to vectorize arrays into column vector as the colon operator does.

3 Kommentare

We did, a very long time ago. It's called reshape.
A = magic(5);
B = reshape(A, [], 1);
% or to avoid the need to implicitly compute the "missing" size
% inside reshape
C = reshape(A, numel(A), 1);
Jan
Jan am 10 Okt. 2017
Bearbeitet: Jan am 10 Okt. 2017
@Royi: Do you have an example where the mentioned methods are not applicable or "ugly"?
Royi Avital
Royi Avital am 15 Jan. 2019
@Jan, I find something like vec(A) to be much more elegant.

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Jan
Jan am 10 Okt. 2017

0 Stimmen

What's wrong with:
y = x(:)
or:
reshape(x, [], 1)
There is a functional form of the x(:) operator:
subsref(x, struct('type', '()', 'subs', {{':'}}))

1 Kommentar

Sometimes it is easiest to define an auxillary function, such as
column = @(M) M(:);
after which you can
column(a(2:end)) .* column(b(2:end))

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Gefragt:

am 18 Sep. 2012

Kommentiert:

am 15 Jan. 2019

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