numerical solution of predator-prey model
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ahed salman
am 8 Okt. 2019
Kommentiert: Stephan
am 8 Okt. 2019
Hello all, I have a 3d predator prey system and i want to solve it numerically in order to analyze it, I am new to Matlab, used it couples of time before and i beg you for help as i am writing my thesis now, below is the code i used but it seems not to work and i have errors i do not understant in order to fix! Please Help!!!
function signal
%initial conditions
x0=1; y0=1; z0=1;
IC=[x0,y0,z0];
t = 0:.1:60;
r=15;
b=0.05433;
beta=0.9;
rho= .7;
delta= .2;
m= .2;
[t,s]= ode45(@RHS, t,IC );
plot(t ,s(:,2),'linewidth',2,'color','b')
grid on;
xlabel('t', 'FontSize', 20);
ylabel('\omega', 'FontSize', 20);
function dsdt= RHS(t,s)
dsdt_1=r*(s(1)+s(2))-b*s(1)*(s(1)+s(2))-beta*s(1)*s(3)/(1+beta*s(1))-s(1)*(1+s(3)*s(2))/(1+s(3));
dsdt_2=s(1)*(1+s(3)*s(2))/(1+s(3))-b*s(2)*(s(1)+s(2))-rho*beta*s(2)*s(3)/(1+beta*s(2));
dsdt_3=delta*s(1)*s(3)/(1+beta*s(1))+rho*delta*s(2)*s(3)/(1+beta*s(2))-m*s(3);
dsdt=[dsdt_1;dsdt_2,dsdt_3];
end
end
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Akzeptierte Antwort
Stephan
am 8 Okt. 2019
Bearbeitet: Stephan
am 8 Okt. 2019
Problem was here:
dsdt=[dsdt_1;dsdt_2,dsdt_3];
it should be:
dsdt=[dsdt_1;dsdt_2;dsdt_3];
Then it works.
function signal
%initial conditions
x0=1; y0=1; z0=1;
IC=[x0,y0,z0];
t = 0:.1:60;
r=15;
b=0.05433;
beta=0.9;
rho= .7;
delta= .2;
m= .2;
[t,s]= ode45(@RHS, t,IC );
plot(t ,s(:,2),'linewidth',2,'color','b')
grid on;
xlabel('t', 'FontSize', 20);
ylabel('\omega', 'FontSize', 20);
function dsdt= RHS(t,s)
dsdt_1=r*(s(1)+s(2))-b*s(1)*(s(1)+s(2))-beta*s(1)*s(3)/(1+beta*s(1))-s(1)*(1+s(3)*s(2))/(1+s(3));
dsdt_2=s(1)*(1+s(3)*s(2))/(1+s(3))-b*s(2)*(s(1)+s(2))-rho*beta*s(2)*s(3)/(1+beta*s(2));
dsdt_3=delta*s(1)*s(3)/(1+beta*s(1))+rho*delta*s(2)*s(3)/(1+beta*s(2))-m*s(3);
dsdt=[dsdt_1;dsdt_2;dsdt_3];
end
end
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