Iterations on field conditions of a structure array
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SS
am 7 Okt. 2019
Kommentiert: Piyush Dubey
am 11 Nov. 2019
Hi. I am working with a structure array S (1 X 50,000) with 10 fields. I want to find few paramters based on few conditions. Is there a simple way to do such iterations shown below using a loop and save them in a structure?
f1 = [S.f1];
f2 = [S.f2];
f3 = [S.f3];
%% ITERATION 1:
idx1 = f1 > 0 & f1 <=10;
% Parameter 1
num1 = numel(f1(idx1));
avg1 = mean(f2(idx));
sd1 = std(f2(idx));
% Parameter 2
idx2 = f3 > 0;
idx = idx1 & idx2;
pos_num1 = numel(f1(idx));
pos_avg1 = mean(f2(idx));
pos_sd1 = std(f2(idx));
% Parameter 3
idx2 = f3 < 0;
idx = idx1 & idx2;
neg_num1 = numel(f1(idx));
neg_avg1 = mean(f2(idx));
neg_sd1 = std(f2(idx));
%% ITERATION 2:
idx1 = f1 > 10 & f1 <=20;
% Parameter 1
num2 = numel(f1(idx1));
avg2 = mean(f2(idx));
sd2 = std(f2(idx));
% Parameter 2
idx2 = f3 > 0;
idx = idx1 & idx2;
pos_num2 = numel(f1(idx));
pos_avg2 = mean(f2(idx));
pos_sd2 = std(f2(idx));
% Parameter 3
idx2 = f3 < 0;
idx = idx1 & idx2;
neg_num2 = numel(f1(idx));
neg_avg2 = mean(f2(idx));
neg_sd2 = std(f2(idx));
% so on till 20 interations.
The result should be saved like:
Result.num=[num1,num2,num3.........,num20];
Result.pos_num=[pos_num1,pos_num2,pos_num3,.....,pos_num20];
Result.neg_num=[neg_num1,neg_num2,neg_num2,......,neg_num20];
Result.avg=[avg1,avg2,avg3,.....avg20];
.. so on.
Any help will be highly appreciated.
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Akzeptierte Antwort
Piyush Dubey
am 10 Okt. 2019
Hi,
It is not very clear from your explanation what you are trying to accomplish. If you are trying to iterate using indices that satisfy some conditions, you should make a matrix with each column containing indices of vector 'f1' that satisfy the required conditions. For example,
idx_list = [(f1 > 0 & f1 <= 10) (f1 > 10 & f1 <= 20) (f1 > 20 & f1 <= 30)];
idx_list_size = 3;
num_list = zeros(idx_list_size, 1);
And iterate in the following way:
for i=1:idx_list_size
num_list(i) = numel(f1(idx_list(:, i)));
end
2 Kommentare
Piyush Dubey
am 11 Nov. 2019
You can save a list to a structure as follows:
Result.num_list = num_list;
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