How to find the nth is the higher than and closest to 0.3

2 Ansichten (letzte 30 Tage)
A=[5 56 6.1 0.29 0.32 15 ]
I want to find a value which not only be the closest to 0.3,but also higher than 0.3
As we know ,0.32 should be the answer,and 0.32 is the 5th number in A vector,how do i write a code to let Matlab tell the 5th is higher and closest number to 0.3 ?

Akzeptierte Antwort

Star Strider
Star Strider am 2 Okt. 2019
One approach:
A=[5 56 6.1 0.29 0.32 15 ];
Av = A(A > 0.3);
[~,idx] = min(abs(Av-0.3));
Out = Av(idx)
Idx = find(A == Out)
producing:
Out =
0.32
Idx =
5
This first selects the elements of ‘A’ that are larger than 0.3, then finds the closest value to 0.3. It then uses that value to find the position in ‘A’. (I also tested this on some random ‘A’ vectors.)

Weitere Antworten (1)

Shubham Gupta
Shubham Gupta am 2 Okt. 2019
One of the several ways:
A=[5 56 6.1 0.29 0.32 15 ];
[vec,ind] = sort(A);
id = find(vec>0.3,1);
rqd_value = vec(id) % Required Value
rqd_index = ind(id) % Required Index

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