Sum of alternating series

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Britnie Casillas
Britnie Casillas am 27 Sep. 2019
Beantwortet: Star Strider am 27 Sep. 2019
How do you find the sum of a series with alternate signs. I know how to find with same signs but not alternating. I have no idea where to start. For example, 1-(1/3)+(1/5)-(1/7)+(1/9)...-(1/1003) with the sum equaling to 0.7849~pi/4
*This is not a homework problem. This is a studying question for my upcoming exam. I am very new to matlab and do not know where to start.

Akzeptierte Antwort

Star Strider
Star Strider am 27 Sep. 2019
Just create the series and use the sum function:
N = 1003;
frc = (1./(1:2:N));
exv = (-1).^(0:numel(frc)-1);
ser = frc.*exv
ser_sum = sum(ser)
ser_sum =
0.784900155923366

Weitere Antworten (1)

jeewan atwal
jeewan atwal am 27 Sep. 2019
Please go through following link:
https://www.quora.com/Why-is-1-1-3-+-1-5-1-7-+-1-9-%CF%80-4

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