problems using && with dropdown list result
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Muazma Ali
am 24 Sep. 2019
Bearbeitet: Muazma Ali
am 24 Sep. 2019
hi!
S={'NH4Cl'; 'MgCl2'; 'CaCl2'; 'ZnCl2'; 'ZnSO4'; 'NaCl'};
>> str={'Choose the combinations of salts available'};
>> result=listdlg('Promptstring',str, 'ListSize', [100,100], 'ListString', S, 'SelectionMode', 'multiple');
>> if result==1&&result==3
disp('hei')
end
the error I get: Operands to the || and && operators must be convertible to logical scalar values. Donnt understand because the output from result is scalar and is should be possible to use && togehter with scalar outputs..
4 Kommentare
the cyclist
am 24 Sep. 2019
Muazma,
The problem with your code is clear to me (and Adam). You have allowed the user to select multiple items. For example, they might select 'NH4Cl' and 'CaCl2'. In this case,
result = [1 3]
and you are trying to evaluate
[1 3]==1 && [1 3]==3
which is
[1 0] && [0 1] % these are logical vectors
These are not allowable operands for the short-circuit logical operators. The operands must each be a single scalar value.
What is not clear to me is what you want to happen in your if statement. Perhaps you could explain this more completely.
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the cyclist
am 24 Sep. 2019
Here is what I think you want, based on your most recent comment:
if all(ismember([1 3],result))
disp('hei')
end
The if statement will be entered if the user's selections include 'NH4Cl' and 'CaCl2'.
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Weitere Antworten (1)
the cyclist
am 24 Sep. 2019
My best guess as to what you want is
if any(ismember(result,[1 3]))
disp('hei')
end
The if statement will be entered if the user's selections include 'NH4Cl' or 'CaCl2' (or both).
2 Kommentare
Guillaume
am 24 Sep. 2019
Maybe the OP wants all instead of any. I.e all the selections must be NH4Cl or CaCl2
if all(ismember(result, [1 3]))
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