Plot 3D matrix with complex values

I have a matrix of complex values (a i +b), with shape 128 * 8 * 121. How can I plot it, please ?
Thank you so much in advance :)

6 Kommentare

darova
darova am 23 Sep. 2019
What those values represent?
nour besbes
nour besbes am 23 Sep. 2019
It represent the result of the stft matlab function
darova
darova am 23 Sep. 2019
Where those values should be on the graph?
nour besbes
nour besbes am 23 Sep. 2019
I want to have a graph like this one.
stft.png
darova
darova am 23 Sep. 2019
What do dimension mean? (128 x 8 x 121) ?
nour besbes
nour besbes am 23 Sep. 2019
it's a 3D matrix. It means 8 matrix of (128 rows X 121 columns ) size.

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Antworten (3)

Matt J
Matt J am 23 Sep. 2019
Bearbeitet: Matt J am 23 Sep. 2019

1 Stimme

One way,
plot(a(:),b(:),'x')
darova
darova am 23 Sep. 2019

0 Stimmen

Try pcolor
pcolor(A(:,1,:)) % display first matrix
Sara James
Sara James am 21 Okt. 2019

0 Stimmen

As another mentioned previously, use pcolor. Note that since your signal is complex, you will have to take the absolute value first as follows:
fs = 3000; % Sampling frequency (Hz)
t = 0:1/fs:1-1/fs; % Time (sec)
x = [exp(2j*pi*100*cos(2*pi*2*t))+randn(size(t))/100; ...
exp(2j*pi*100*cos(0.5*pi*2*t))+randn(size(t))/100; ...
exp(2j*pi*100*cos(1*pi*2*t))+randn(size(t))/100]'; % Multi-channel signal
[S,F,T] = stft(x,fs,'Window',hamming(128,'periodic'),'OverlapLength',50);
smag = mag2db(abs(S)); % Convert to dB
caxisLims = max(smag(:)) + [-60 0]; % Color axis limits
figure('Name','STFT')
numChannels = size(x,2);
for ii = 1:numChannels
subplot(2,2,ii)
pcolor(T,F,smag(:,:,ii))
xlabel('Time (s)')
ylabel('Frequency (Hz)')
shading flat
hC = colorbar;
hC.Limits = caxisLims;
hC.Label.String = 'Magnitude (dB)';
title(sprintf('Channel %d',ii))
end
sgtitle('Spectrogram')

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Gefragt:

am 23 Sep. 2019

Beantwortet:

am 21 Okt. 2019

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