Remove NaN inside a loop cycle

Given the following code

V = [ 19 15 11 2 16 3 1 18 14 3 18 19 1 13 16 14 19 15 4 14 3 1 2 16 4 3 1 19 3 20 4 13 1 15 2 18 4 1 19 17 3 1 13 3 4 17 18 19 14  ;
    19 16 11 2 16 15 1 18 14 3 18 19 14 2 16 14 19 15 4 14 3 11 2 16 4 3 1 19 3 20 4 13 1 4 2 18 4 1 19 17 3 19 13 3 4 17 18 19 14 ];
A=      [0  15 11 2 4  0  3 1 13;
        14  0 16 0 0  0  0 0 0;
        0   0 0  0 8  0  0 0 0;
        0   0 18 0 0  0  0 0 0;
        0   0 19 0 0  0  0 0 0;
        0   0 0  0 0  0  0 0 0];
%V = [V(1,:), NaN(1, mod(-size(V,2), 10))];


for i= 1:size(V,1)
VVV = [V(i,:), NaN(1, mod(-size(V,2), 10))];
%assert(mod(numel(V), 10) == 0, 'V length is not a multiple of 10');
V10 = reshape(VVV, 10, []);  %rearrange V in batches of 10
[~, where] = ismember(V10, A);  %find location of elements in A
[~, col] = ind2sub(size(A), where);  %convert location into column index
[~, order] = sort(col, 1);  %and sort by column order
X (i,:) = reshape(V10(order + (0:size(order, 1):numel(order)-1)), 1, []);  %and rearrange columns of V10 according to that order
B(i,:) = X(~isnan(X(i,:)))';
end

I'm generating a matrix X where inside are contained some NaN. How can I remove the NaN inside the rows?

the code

B(i,:) = X(~isnan(X(i,:)))';

does not work!

The number of NaN is the same in each rows, so we don't need to use cells

May someone help me?

Answer 1

[Star Strider]

Try this:

B(i,:) = X(i,~isnan(X(i,:)));