Finding consecutive data with non zero in array
13 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
edward kabanyas
am 15 Sep. 2019
Bearbeitet: edward kabanyas
am 7 Okt. 2019
Hi all;
I want to find consecutive data with non zero value in array. However, as long as the data with 0 value is less than 3 points, it is still considered as part of the previous data set. The data with the same length is classified into same array.
For example:
xx = [1 2 3 0 1 2 0 0 0 1 2 3 4 0 1 0 0 0 1 1 1];
The expected result
xx1 =[1 2 3 0 1 2; 1 2 3 4 0 1];
xx2=[1 1 1];
I try to find it using looping procedure but it takes only onsecutive data with non zero value and I can not find the solution for this criteria "as long as the data with 0 value is less than 3 points".
Hope some help.
Thank you.
Edward
2 Kommentare
Rik
am 15 Sep. 2019
Numbered variables are a bad idea. Also, it should be feasible to adapt your code to also work for the shorter runs of zeros. Can you share your code here? Attach it in an m file if it is more than about 20 lines long.
Otherwise, you could try the RunLength FEX submission by Jan to find the run lengths and continue from there.
Rik
am 16 Sep. 2019
Comment posted as answer by edward kabanyas:
Thank you Rik. The following is my code:
threshold = 0;
transitions = diff([0, xx > threshold, 0]);
runstarts = find(transitions == 1);
runends = find(transitions == -1) - 1;
blocks = arrayfun(@(s, e) xx(s:e), runstarts, runends, 'UniformOutput', false);
celldisp(blocks)
However, it takes only onsecutive data with non zero value and I can not find the solution for the criteria "as long as the data with 0 value is less than 3 points". Then, the cell with same size in blocks is not merged into one cell as I need above.
Akzeptierte Antwort
Andrei Bobrov
am 16 Sep. 2019
Bearbeitet: Andrei Bobrov
am 5 Okt. 2019
for R2013a (and for your data from all_data.txt)
f = fopen('all_data.txt');
Data = textscan(f,'%f %f %f %f %f %f %f','CollectOutput',1);
fclose(f);
Data = Data{:};
lo = any(Data(:,6:7) ~= 0,2);
d = find(lo);
ii = [true;diff(d) > 3];
i2 = ii([2:end,1]);
i = zeros(size(Data,1),1);
i(d(ii)) = 1;
i(d(i2) + 1) = -1;
j = cumsum(i);
jj = cumsum([false;diff(j) == 1]).*j;
out = accumarray(jj+1,(1:size(Data,1))',[],@(x){Data(sort(x),:)});
out = out(2:end);
10 Kommentare
Weitere Antworten (1)
Rik
am 16 Sep. 2019
I used the mfile version of Jan's FEX submission RunLength, because I can't get my compiler to work right now. With the runlegth determined it is relatively easy to find the groups that need to be merged. Then you can still use the code you proposed to find the transitions.
xx = [1 2 3 0 1 2 0 0 0 1 2 3 4 0 1 0 0 0 1 1 1];
[a,b]=RunLength_M(xx~=0);
L= a(:)==false & b<3;%to be merged
%checks for egde cases should be perfomed here:
%-first group is a small group of zeros
%-last group is a small group of zeros
L_prev=[L(2:end);false];
L_next=[false;L(1:(end-1))];
b(L_prev)=b(L_prev)+b(L)+b(L_next);
a(L | L_next)=[];%remove merged parts
b(L | L_next)=[];%remove merged parts
x=RunLength_M(a,b);
transitions = diff([0, RunLength_M(a,b), 0]);
runstarts = find(transitions == 1);
runends = find(transitions == -1) - 1;
blocks = arrayfun(@(s, e) xx(s:e), runstarts, runends, 'UniformOutput', false);
celldisp(blocks)
5 Kommentare
Rik
am 3 Okt. 2019
What I meant to ask is if you were using a matrix or a vector a input. Attaching the data as a mat file would probably work best.
Rik
am 5 Okt. 2019
Bearbeitet: Rik
am 5 Okt. 2019
It turns out you also need to use (:) for b if your input is a column vector. I just tested this on R2011a, so it should also works on ancient releases. I'll edit my answer.
Edit: except that your example is integer only and your data isn't, which seems to be causing problems.
Siehe auch
Kategorien
Mehr zu String Parsing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!