Using 3D array to subtract row Q from row P

1 Ansicht (letzte 30 Tage)
Sara Foster
Sara Foster am 7 Sep. 2019
Kommentiert: Sara Foster am 7 Sep. 2019
If I have a test array e.g C = [100,100,100;50,50,50;40,40,40] and I use the command P = C(1,1,:), it will give me a value of 100 (which is the first P1 pixel) and using Q = C(3,1,:) it gives me a value of 40.
However I want to use an example function like this to calculate distance between pixels:
P = P(1); P2 = P(2); P3 = P(3);
Q = Q(1); Q2 = Q(2); Q3 = Q(3);
squaredDistance = (P1-Q1)^2 + (P2-Q2)^2 + (P3-Q3)^2;
And P1 and Q1 using squared distance formula only gives me a value of 3600, where I want total squared distance using P2 and P3 & Q2 and Q3 is there any way of doing this without needing to resort to for loops? Thanks!

Antworten (1)

James Tursa
James Tursa am 7 Sep. 2019
Bearbeitet: James Tursa am 7 Sep. 2019
It is unclear what you really want. If you want the Euclidean distance squared between rows, e.g., rows 1 and 3, then just
d = C(1,:) - C(3,:);
result = d * d';
  1 Kommentar
Sara Foster
Sara Foster am 7 Sep. 2019
If I'm using P and Q as input commands, I want to use any row value for these two inputs e.g. I could have Q = C(3,1,:) or Q = C(2,1,:) depending on the input I choose for Q, as my inputs are P and Q and output is the distance.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by