Data visualization using a matlab figure/graph

3 Ansichten (letzte 30 Tage)
Julian
Julian am 5 Sep. 2019
Kommentiert: Julian am 8 Sep. 2019
Hi everyone,
im struggling with visualizing my data in a matlab figure.
Imagin i'm having three collumns.
  1. Label (Label 1, Label 2, Label 3)
  2. Attribute (A1, A2, A3, A4)
  3. Number of Observations
Label 1 A1 3
Label 1 A2 6
Label 2 A2 4
Label 2 A3 8
Label 3 A1 9
Now I want to make a graph out of this where I have the labels on the x-axis, the number of observations on the y-axis. Then in the graph it should be seen how often each attribute was oberserved for each attibute. And then the attributes should be stacked onto each other (differentiated by colour).
I can do this in Excel (see attached image), but I was wondering whether this kind ob visualization is also possible in MATLAB.
example.PNG
Thank you so much in advance.
Julian

Akzeptierte Antwort

Arturo Mendoza Quispe
Arturo Mendoza Quispe am 8 Sep. 2019
If you organize your data as :
% A1 A2 A3 A4
X = [ 3, 7, 0, 0; % Label 1
3, 20, 7, 0; % Label 2
3, 4, 0, 8]; % Label 3
You just need:
bar(X, 'stacked');
If you wish to make it look similar to your example:
labels = {'Label 1', 'Label 2', 'Label 3'};
attributes = {'A1', 'A2', 'A3', 'A4'};
figure;
bar(X, 'stacked');
set(gca,'XTickLabel', labels);
set(gca, 'YGrid', 'on', 'XGrid', 'off');
legend(attributes, 'Location', 'NorthOutside', 'Orientation', 'Horizotnal');
colormap([68 114 196;165 165 165;91 155 213;38 68 120] / 255);
ylim([0, 35]);
title('XX');
Furthermore, assuming the data is stored in three variables (i.e., the columns)
Label = {'Label 1', 'Label 1', 'Label 2', 'Label 2', 'Label 3'};
Attribute = {'A1', 'A2', 'A2', 'A3', 'A1'};
Observations = [3, 6, 4, 8, 9];
The "organization" of the data can be done with
labels = {'Label 1', 'Label 2', 'Label 3'};
attributes = {'A1', 'A2', 'A3', 'A4'};
X = zeros(numel(labels), numel(attributes));
for k = 1:numel(Observations)
i = ismember(labels, Label{k});
j = ismember(attributes, Attribute{k});
X(i, j) = X(i, j) + Observations(k);
end
  1 Kommentar
Julian
Julian am 8 Sep. 2019
Thank you very much, I will let you know if it worked as soon as I can :)

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Produkte


Version

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by