Retime timetable out of bounds
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Rub Ron
am 27 Aug. 2019
Kommentiert: Rub Ron
am 30 Aug. 2019
I have a set of timetables inside a cell TT, each of them with a resolution of 15 minutes, the timetables have different starts and ends, different sizes (missing data for each are different). What I want to do is set all these time tables to a common time vector, and then fill all the missing data with NaN. If I use retime (for one timetable) in this from:
TT1new = retime(TT{1},'regular','fillwithmissing','TimeStep',minutes(15));
it fills NaN but within the time range of TT1, and not of my time vector. So it seems to me that in order to use my time vector "retime" is of no use, instead I have done the following:
tini = datetime({'01-Apr-2016 00:00:00'});
tfin = datetime({'01-Apr-2017 00:00:00'});
timeVector = [tini:datenum([0,0,0,0,15,0]):tfin]';
%I built a reference timetable full of NaN, (I have 3 variables in each timetable)
ttref = timetable(timeVector,NaN(length(timeVector),1),NaN(length(timeVector),1),NaN(length(timeVector),1));
%Then I plan to fill the non-missing data in the reference timetable for each timetable, and capture the result in TTFit
num = length(TT);
TTFit = cell(num,1);
for i=1:num
temp=ttref;
range = timerange(max(tini,TT{i}.Time(1)),min(tfin,TT{i}.Time(end)),'closed');
temp(TT{i}(range,:).Time,:).Variables = TT{i}(range,:).Variables;
TTFit{i}=temp;
end
But it takes an eternity (more than 20 minutes so far and yet dont know if it works) to finish the run. Is there an easier and efficient way to do that? Any hints would be really apreciatted.
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Akzeptierte Antwort
Lei Hou
am 27 Aug. 2019
Hi Rub,
First, about your code examples I have some suggestions. I saw you used datenum in your first post. It is good that you replaced datenum with minutes in your second post. It's never a good idea to mix datenum with the newer and preferred datetime. About preallocating a timetable, you can also do it by using timetable preallocation syntax as the following.
ttref = timetable('Size', [length(timeVector), 3], 'VariableTypes', ["double" "double" "double"], 'RowTimes', timeVector);
To answer your question, retime is the right tool for your job. Retime has a syntax TT2 = retime(TT1,NEWTIMES). You can use TTFit{i}=retime(TT{i},timeVector) in your for-loop. Your code will look like the following:
tini = datetime({'01-Apr-2016 00:15:00'});
tfin = datetime({'07-Apr-2017 00:00:00'});
timeVector = [tini:minutes(15):tfin]';
num = length(TT);
TTFit = cell(num,1);
for i=1:num
TTFit{i}=retime(TT{i},timeVector);
end
Furthermore, you can use cellfun to replace your for-loop as
tini = datetime({'01-Apr-2016 00:15:00'});
tfin = datetime({'07-Apr-2017 00:00:00'});
timeVector = [tini:minutes(15):tfin]';
TTFit = cellfun(@(tt)retime(tt, timeVector),TT,'UniformOutput',false);
This runs faster.
I’m interested in why you put your timetables in a cell array, and what you will do with it next. If you are going to concatenate then all to make one timetable, then synchronize is the tool that can help you. Steve suggested calling synchronize using a comma-separated list, which you may not have seen before. Here's what that looks like:
TTFit = synchronize(TT{:},timeVector);
3 Kommentare
Peter Perkins
am 29 Aug. 2019
Bearbeitet: Steven Lord
am 29 Aug. 2019
Rub, if you have a moment, it would be helpful to hear more about how the data were organized in Excel, for example do you have multiple sheets in one spreadsheet? multiple spreadsheets? multiple folders each containg multiple spreadsheets?.
It would also be helpful to know what you would do next with that cell array of timetables. They will all have the same time vector, so one thing you might do is to horzcat them together (equivalent to what Steve Lord originally suggested). If they represent different measurements from different groups of sensors, that probably makes sense. But if they represent the same measurements juat a different locations, you might want to keep them separate and iterate over them, doing the same cleaning or calculations on each one.
Thanks in advance.
[SL: fixed typo of my name]
Weitere Antworten (2)
Steven Lord
am 27 Aug. 2019
In this case, retime is not the right tool for the job. synchronize them instead. Since you have a cell array of timetable arrays, pass them into synchronize as a comma-separated list.
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