how to compare two matrix with if else statement?

select_win = [4 5 8 9]
mat_t = [0 0 0 0; 1 0 1 0; 0 1 0 0] 
data = [1 0 1 0];

I am trying to compare data matrix with mat_t.

if data array matches with mat_t array I want to write a condition of selecting first row from select_win array else I want to choose 2nd row from select_win array

I am trying to write an if else statement in this but its not working. I am stuck at the point in my code and would genuinely appreciate if someone helps with it.

Answer 1

[Walter Roberson]

? Your select_win only has one row.

Question: is it the corresponding element that is to be chosen?

For row K of mat_t :

select_win( sub2ind(size(select_win), (data == mat_t(K,:)) + 1, 1:size(data,2)) )

[Ayesha Punjabi]

select_win = [4;5;8;9];
mat_t = [0 0 0 0; 1 0 1 0; 0 1 0 0];
data = [1 0 1 0];
if data==mat_t
select_win(1)
else data~=mat_t
select_win(2)
end

I am trying to choose data for 1st column of select_win if my data array matches with mat_t and if it doesn't then I am trying to choose data for 2nd column from select_win

[Ayesha Punjabi]

But its not working properly because if changes mat_t 2nd row to all zeros and it displays 5 which is 2nd column from select_win array

[Walter Roberson]

if data==mat_t
select_win(1)
else data~=mat_t
select_win(2)
end

means the same as

if all( reshape(data==mat_t, [], 1) )
  disp(select_win(1))
else
    disp(data~=mat_t)
    disp(select_win(2))
end

There are elemenets of the vector data that are not equal to the corresponding entries in mat_t, so it is not true that all of the elements are equal, so the else is invoked.

Answer 2

[Matt J]

rownum = all(data==mat_t,2)+1;

select_win( rownum )