if i have a list of numbers and i have to use 'while' loop to determine when the list of numbers decreased by 10000 from initial value , how should i code it ?

3 Kommentare

the cyclist
the cyclist am 20 Aug. 2019
Sounds like a school assignment. Folks here will generally be happy to help if you show what you tried so far, and ask specific questions where you are stuck.
Navikesh Krishna
Navikesh Krishna am 20 Aug. 2019
I tried this but this didnt work :
-while altitude < 10000
-disp(altitude(1,1))
-end
1.PNG
hint:
idx = 1;
while idx.^3 + 5*idx.^2 - 19 < 10000
idx = idx + 1;
end
disp(idx)

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Antworten (1)

AlexG
AlexG am 20 Aug. 2019
Bearbeitet: AlexG am 20 Aug. 2019

0 Stimmen

Not clear what you mean by the initial value but if you mean the first value in the list that is 10000 less than its first value then you could use:
index = find(a <= a(1) - 10000, 1);
Above, a is your vector of numbers, e.g.,
a = [1:3 -10000:0];

1 Kommentar

Navikesh Krishna
Navikesh Krishna am 20 Aug. 2019
this is my initial values given and i have to find when the values deceased by 10000
i tried : while altitude < 10000
disp(altitude(1,1))
end
but it didnt work out
1.PNG

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