Found error "Undefined function 'minus' for input arguments of type 'cell'. Error in @(x,y)1./deff-w(x,y) "

1 Ansicht (letzte 30 Tage)
I tried the integral on w(x,y) equation and it shows the above error..Please help!
a=19.38e-6;
L=2*a;
Cr=3.45;
Cb=4.06;
Cs=1.994;
A=150.454e3;
B=0.0535;
C=12.53e-9;
d0=1e-6
sig=290e6;
t=2.4e-6;
Deff=((A*C)-B^2)/A
k=((Cr*t*sig)/a^2)+((Cb*12*Deff)/a^4) % stifness in pa
area=L*L;
v=0.23;
E=170e9; % young's modulus
Q=E/(1-v^2);
E0=8.854e-12;
K=k*area; % stiffness in N
d0=0:0.1e-6:1e-6 % air gap
Vpi=sqrt((8*(d0.*d0.*d0).*K)/(27.*E0.*area));
figure(1)
plot(d0,Vpi);
xlabel('Gap')
ylabel('V-pullin')
Vb=12;
v=0.23;
di=0.2e-6; % insulator thickness
Erm=11.68; %dielectric constant of polysilicon
Eri=8; % dielectric constant of insulator
Fs=(1-0.271*v)/(1-v)
deff =(t/Erm)+(di/Eri)+d0
Pext=0;
X1=(Cs*Fs*(Q*t/a^4))
X2=0
X3=(((Cr.*t.*sig)./(a.^2))+((Cb.*12.*Deff)./(a.^4))-((E0.*Vb.^2)./2.*a)).*((4.*a)./deff.^3)+((0.394).*(a.^0.25)./(deff.^2.25))
X4=-(Pext+((E0.*Vb.^2)./2.*a)).*((2.*a)./deff.^2)+((0.315).*(a.^0.25)./(deff.^1.25))
W0= roots([X1 X2 X3 X4])
for n=1:length(W0)
if((imag(W0(n)==0)))
W0=W0(n);
end
end
Vb= 0:5:50
P1=((E0.*Vb.^2)./2.*a).*(((2.*a)./d0.^2)+((.265.*((2.*a).^0.25))./(d0.^1.25)))
P2= ((E0.*Vb.^2)./2.*a).*((4.*a./d0.^3)+((0.33125.*((2.*a).^(0.25)))./d0.^2.25))
W=abs(W0);
W1=W(1:2:end,:)
W1(12,:)=[];
W2= W1.'
P3= P2.*W2;
Pelec = P1+P3
figure(2)
plot(Pelec,Vb);
xlabel('Electrostatic Pressure')
ylabel('Bias Voltage')
figure(3)
plot(Vb,W2);
xlabel('Bias Voltage')
ylabel('Center Deflection')
syms w(x,y)
c(1) = 1
c(2) = 0.6832
c(3) = 0.3105
syms x y
S = sum(c(1:3).*(((x^2+y^2)/a^2).^n-1),1,3)
symvar(S,2)
w(x,y) = W0.*(1-x.^2/a.^2).^2 .*(1-y.^2/a.^2).^2 .* S;
wu = w(x,y)
fun = @(x,y) 1./deff - w(x,y); %error
q = integral2(fun,0,L,0,1e-6);
Cdeform= E0.*q;
Cff= (0.385.*deff)./a + 1.06.*((1./L).*deff).^(0.75) + (0.53./a).*(1e-6.*deff).^(0.5)
Cap = Cdeform.*(1+Cff)
figure(4)
plot(Vb,Cap)
xlabel('Bias Voltage')
ylabel('Capacitance')

Antworten (0)

Kategorien

Mehr zu General Physics finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by