Negative output Fsolve Function

6 Ansichten (letzte 30 Tage)
K.G
K.G am 31 Jul. 2019
Beantwortet: Sai Sri Pathuri am 7 Aug. 2019
Hi all,
can anyone help me understand why I am getting a negative output from this code and how can I modify the code so I do not get a negative output?
function [x,exitflag]= Function_final(c)
c=[10^-7,10^-7,0.5*10^-3,0.5*10^-3,0.25*10^-3,0.25*10^-3,0.25*10^-3,0.25*10^-3,0.5*10^-3,0.5*10^-3,0.5*10^-3,0.5*10^-4,0.25*10^-1,0.5*10^-4,0.5*10^-6];
MaT = c(3)+c(4)+c(9)+c(10)+c(11)+c(12);
MbT = c(5)+c(6)+c(7)+c(8)+c(9)+c(10)+c(11);
McT = c(2)+c(6)+2*c(7)+3*c(8)+c(9)+2*c(10)-c(1)-c(4)+c(13)+2*c(15)+c(12);
MdT = c(12)+c(13)+c(14)+c(15);
z=[1,1,2,1,3,2,1,0,0,1,1,1,1,2,0];
T=36;
I=0.5*sum(c.*z.^2);
A=0.486+(6.07*10^-4)*T+(6.43*10^-6)*T^2;
gamma_initial=zeros(1,15);
for i=1:15
gamma_initial(i)=10^(-A*z(i)^2*(I^0.5/(1+I^0.5)-0.3*I));
end
p = [gamma_initial, c];
options=optimoptions('fsolve','Display','iter');
[x,exitflag]=fsolve(@(x)Approach(x,MaT,MbT,McT,MdT),p,options);
end
function F = Approach(p,MaT,MbT,McT,MdT)
K1 = 1.01*10^-14;
K2 = 2.13*10^-13;
K3 = 1.14*10^12;
K4 = 1.73*10^19;
K5 = 2.71*10^21;
K6 = 5.36*10^14;
K7 = 3.41*10^20;
K8 = 1.18*10^7;
K9 = 4.01;
K10= 1.74*10^10;
K11 = 3.09*10^3;
z=[1,1,2,1,3,2,1,0,0,1,1,1,1,2,0];
T=36;
A=0.486+(6.07*10^-4)*T+(6.43*10^-6)*T^2;
c = p(16:30);
la = log10(p(1:15));
I=0.5*sum(c.*z.^2);
F(1) = la(1)^2 - la(1) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(2) = la(2)^2 - la(2) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(3) = la(3)^2 - la(3) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(4) = la(4)^2 - la(4) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(5) = la(5)^2 - la(5) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(6) = la(6)^2 - la(6) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(7) = la(7)^2 - la(7) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(8) = la(8)^2 - la(8) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(9) = la(9)^2 - la(9) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(10) = la(10)^2 - la(10) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(11) = la(11)^2 - la(11) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(12) = la(12)^2 - la(12) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(13) = la(13)^2 - la(13) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(14) = la(14)^2 - la(14) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(15) = la(15)^2 - la(15) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(16) = (K1*(10^la(2)*p(17))^(-1))-(10^la(1)*p(16));
F(17) = (K2*(10^la(3)*p(18))*(10^la(1)*p(16)))-(10^la(4)*p(19));
F(18) = (K3*(10^la(5)*p(20))*(10^la(2) *p(17)))-(10^la(6)*p(21));
F(19) = (K4*(10^la(5)*p(20))*(10^la(2)*p(17))^2)-(10^la(7)*p(22));
F(20) = (K5*(10^la(5)*p(20))*(10^la(2)*p(17))^3)-(10^la(8)*p(23));
F(21) = (K6*(10^la(3)*p(18))*(10^la(5)*p(20))*(10^la(2)*p(17)))-(10^la(9)*p(24));
F(22) = (K7*(10^la(3)*p(18))*(10^la(5)*p(20))*(10^la(2)*p(17))^2)-(10^la(10)*p(25));
F(23) = (K8*(10^la(3)*p(18))*(10^la(5)*p(20)))-(10^la(11)*p(26));
F(24) = (K9*(10^la(3)*p(18))*(10^la(14)*p(29))*(10^la(2)*p(17)))-(10^la(12)*p(27));
F(25) = (K10*(10^la(2)*p(17))*(10^la(14)*p(29))) - (10^la(13)*p(28));
F(26) = (K11*((10^la(2)*p(17))^2)*(10^la(14)*p(29))) - (10^la(15)*p(30));
F(27) = p(18)+p(19)+p(24)+p(25)+p(26)-MaT;
F(28) = p(20)+p(21)+p(22)+p(23)+p(24)+p(25)+p(26)-MbT;
F(29) = p(17)+p(21)+2*p(22)+3*p(23)+p(24)+2*p(25)-p(16)-p(19)-McT;
F(30) = p(27)+p(28)+p(29)+p(30)-MdT;
F = [F(1);F(2);F(3);F(4);F(5);F(6);F(7);F(8);F(9);F(10);F(11);F(12);F(13);F(14);F(15);F(16);F(17);F(18);F(19);F(20);F(21);F(22);F(23);F(24);F(25);F(26);F(27);F(28);F(29);F(30);
end

Akzeptierte Antwort

Sai Sri Pathuri
Sai Sri Pathuri am 7 Aug. 2019
The negative value for exitflag is obtained because the equation is not solved due to tolerances. Try to execute by setting the appropriate values of tolerances.
Refer the following link for troubleshooting

Weitere Antworten (0)

Kategorien

Mehr zu Component-Based Modeling finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by