Negative output Fsolve Function
6 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
K.G
am 31 Jul. 2019
Beantwortet: Sai Sri Pathuri
am 7 Aug. 2019
Hi all,
can anyone help me understand why I am getting a negative output from this code and how can I modify the code so I do not get a negative output?
function [x,exitflag]= Function_final(c)
c=[10^-7,10^-7,0.5*10^-3,0.5*10^-3,0.25*10^-3,0.25*10^-3,0.25*10^-3,0.25*10^-3,0.5*10^-3,0.5*10^-3,0.5*10^-3,0.5*10^-4,0.25*10^-1,0.5*10^-4,0.5*10^-6];
MaT = c(3)+c(4)+c(9)+c(10)+c(11)+c(12);
MbT = c(5)+c(6)+c(7)+c(8)+c(9)+c(10)+c(11);
McT = c(2)+c(6)+2*c(7)+3*c(8)+c(9)+2*c(10)-c(1)-c(4)+c(13)+2*c(15)+c(12);
MdT = c(12)+c(13)+c(14)+c(15);
z=[1,1,2,1,3,2,1,0,0,1,1,1,1,2,0];
T=36;
I=0.5*sum(c.*z.^2);
A=0.486+(6.07*10^-4)*T+(6.43*10^-6)*T^2;
gamma_initial=zeros(1,15);
for i=1:15
gamma_initial(i)=10^(-A*z(i)^2*(I^0.5/(1+I^0.5)-0.3*I));
end
p = [gamma_initial, c];
options=optimoptions('fsolve','Display','iter');
[x,exitflag]=fsolve(@(x)Approach(x,MaT,MbT,McT,MdT),p,options);
end
function F = Approach(p,MaT,MbT,McT,MdT)
K1 = 1.01*10^-14;
K2 = 2.13*10^-13;
K3 = 1.14*10^12;
K4 = 1.73*10^19;
K5 = 2.71*10^21;
K6 = 5.36*10^14;
K7 = 3.41*10^20;
K8 = 1.18*10^7;
K9 = 4.01;
K10= 1.74*10^10;
K11 = 3.09*10^3;
z=[1,1,2,1,3,2,1,0,0,1,1,1,1,2,0];
T=36;
A=0.486+(6.07*10^-4)*T+(6.43*10^-6)*T^2;
c = p(16:30);
la = log10(p(1:15));
I=0.5*sum(c.*z.^2);
F(1) = la(1)^2 - la(1) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(2) = la(2)^2 - la(2) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(3) = la(3)^2 - la(3) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(4) = la(4)^2 - la(4) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(5) = la(5)^2 - la(5) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(6) = la(6)^2 - la(6) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(7) = la(7)^2 - la(7) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(8) = la(8)^2 - la(8) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(9) = la(9)^2 - la(9) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(10) = la(10)^2 - la(10) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(11) = la(11)^2 - la(11) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(12) = la(12)^2 - la(12) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(13) = la(13)^2 - la(13) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(14) = la(14)^2 - la(14) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(15) = la(15)^2 - la(15) * (I*A*z(1)^2) * 2.6 - 1/(1-I)^2 * A^2 * z(1)^4 * (I - 1.69 * I^2 - 0.09 * I^4);
F(16) = (K1*(10^la(2)*p(17))^(-1))-(10^la(1)*p(16));
F(17) = (K2*(10^la(3)*p(18))*(10^la(1)*p(16)))-(10^la(4)*p(19));
F(18) = (K3*(10^la(5)*p(20))*(10^la(2) *p(17)))-(10^la(6)*p(21));
F(19) = (K4*(10^la(5)*p(20))*(10^la(2)*p(17))^2)-(10^la(7)*p(22));
F(20) = (K5*(10^la(5)*p(20))*(10^la(2)*p(17))^3)-(10^la(8)*p(23));
F(21) = (K6*(10^la(3)*p(18))*(10^la(5)*p(20))*(10^la(2)*p(17)))-(10^la(9)*p(24));
F(22) = (K7*(10^la(3)*p(18))*(10^la(5)*p(20))*(10^la(2)*p(17))^2)-(10^la(10)*p(25));
F(23) = (K8*(10^la(3)*p(18))*(10^la(5)*p(20)))-(10^la(11)*p(26));
F(24) = (K9*(10^la(3)*p(18))*(10^la(14)*p(29))*(10^la(2)*p(17)))-(10^la(12)*p(27));
F(25) = (K10*(10^la(2)*p(17))*(10^la(14)*p(29))) - (10^la(13)*p(28));
F(26) = (K11*((10^la(2)*p(17))^2)*(10^la(14)*p(29))) - (10^la(15)*p(30));
F(27) = p(18)+p(19)+p(24)+p(25)+p(26)-MaT;
F(28) = p(20)+p(21)+p(22)+p(23)+p(24)+p(25)+p(26)-MbT;
F(29) = p(17)+p(21)+2*p(22)+3*p(23)+p(24)+2*p(25)-p(16)-p(19)-McT;
F(30) = p(27)+p(28)+p(29)+p(30)-MdT;
F = [F(1);F(2);F(3);F(4);F(5);F(6);F(7);F(8);F(9);F(10);F(11);F(12);F(13);F(14);F(15);F(16);F(17);F(18);F(19);F(20);F(21);F(22);F(23);F(24);F(25);F(26);F(27);F(28);F(29);F(30);
end
0 Kommentare
Akzeptierte Antwort
Sai Sri Pathuri
am 7 Aug. 2019
The negative value for exitflag is obtained because the equation is not solved due to tolerances. Try to execute by setting the appropriate values of tolerances.
Refer the following link for troubleshooting
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Component-Based Modeling finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!