Can anyone suggest something that could fix the program

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Titu Thomas
Titu Thomas am 30 Jul. 2019
Beantwortet: Prabhan Purwar am 2 Aug. 2019
clear all
clc
%following line calls my data
[xdataini, ydataini] = textread('data.txt','%f %f','headerlines',0);
figure;
plot(xdataini,ydataini,'ok')
ylim([0,1]);
xlim([0,0.25]);
%warning off MATLAB:divideByZero
xdata=xdataini(1:245);
ydata=ydataini(1:245);
x0=[1,1];
[x]=lsqcurvefit(@subprogramTL,x0,xdata,ydata);
V=subprogramTL([x],xdata);
fid = fopen('data1.txt','w');
fprintf(fid,'%3.5f \n',V);
fclose(fid);
hold on
plot (xdata,V,'r')
hold off
SUBPROGRAM
function F=subprogramTL(x,xdata)
m = 5.8;
v = 1.7;
F=(1-((x(1)/2).*atan((2.*m.*v)/((1+2.*m)^2 + v^2)*(x(2)./(2*xdata)) + 1 + 2.*m + v.^2))).^2;
%+ ((x(1)/4).*log(((1+((2*m)./(1+(2*xdata)/x(2)))).^2 + v.^2)/((1+(2*m)).^2 +v.^2)).^2);
end
  2 Kommentare
Alex Mcaulley
Alex Mcaulley am 30 Jul. 2019
What is your issue? Are you getting any error?
Titu Thomas
Titu Thomas am 30 Jul. 2019
There is no error while running the code, but the curve does not fit with the data points

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Antworten (1)

Prabhan Purwar
Prabhan Purwar am 2 Aug. 2019
Code is working perfectly fine. The output of lsqcurvefit() function is the best fit of variables and depends upon assigned model. For more information refer to following link:
As the data appears to be like an exponential function, then I would suggest you make use of fit() function with appropriate fittype and fitoption as explained in the following example.
fo = fitoptions('Method','NonlinearLeastSquares',...
'Lower',[0,0],...
'Upper',[Inf,max(cdate)],...
'StartPoint',[1 1]);
ft = fittype('a*(x-b)^n','problem','n','options',fo);
[curve2,gof2] = fit(cdate,pop,ft,'problem',2)
For more information refer to following link:

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