Plot best fit line in log-space & get slope

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newbie9
newbie9 am 27 Jul. 2019
Kommentiert: Angie Brulc am 7 Mär. 2022
I am trying to determine the slope of the best-fit line in log space, and plot the best-fit line as a visual check. It needs to be a line, not a curve (I understand that the misfits could be very large in logspace). Below is an example with xy data and polyfit attempts (and plot included). Thanks for any help
x = [7.94, 16.23, 32.92, 66.8, 135.52, 274.93, 557.78, 1131.59, 2295.72, 4657.46];
y = [134000, 102000, 31000, 11000, 2600, 990, 40, 10.41, 3.48, 1.037];
scatter(x,y, 'DisplayName', 'MyData')
set(gca,'xscale','log')
set(gca,'yscale','log')
hold on
grid on
box on
axis equal
p = polyfit(log10(x), log10(y), 1);
z = polyval(p, log10(x));
loglog(x, log10(z), 'DisplayName', 'Try1');
loglog(x, z, 'DisplayName', 'Try2');
z2 = polyval(p, x);
loglog(x, z2, 'DisplayName', 'Try3');
loglog(x, log10(z2), 'DisplayName', 'Try4');
legend
Capture.JPG

Akzeptierte Antwort

Star Strider
Star Strider am 27 Jul. 2019
You are regressing ‘log10(x)’ against ‘log10(y)’ so you need to give the appropriate information to both polyfit and polyval:
Bp = polyfit(log10(x), log10(y), 1);
Yp = polyval(Bp,log10(x));
figure
plot(log10(x), log10(y), 'pg')
hold on
plot(log10(x), Yp, '-r')
hold off
grid
producing this plot:
The slope is -2.0182.
  4 Kommentare
newbie9
newbie9 am 3 Aug. 2019
thanks, that's what I have below
Star Strider
Star Strider am 3 Aug. 2019
As always, my pleasure.
I was working on it as you were posting.

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Weitere Antworten (1)

newbie9
newbie9 am 3 Aug. 2019
Star Strider basically gave the correct answer, so I have accepted; but I wanted to show the fit in log-log space, so here's my version of code, considering Star Strider's answer, in case it is useful to anyone else:
x = [7.94, 16.23, 32.92, 66.8, 135.52, 274.93, 557.78, 1131.59, 2295.72, 4657.46];
y = [134000, 102000, 31000, 11000, 2600, 990, 40, 10.41, 3.48, 1.037];
scatter(x,y, 'DisplayName', 'MyData')
set(gca,'xscale','log')
set(gca,'yscale','log')
hold on
grid on
box on
axis equal
%
Bp = polyfit(log10(x), log10(y), 1);
Yp = polyval(Bp, log10(x));
Yp2 = 10.^(Yp);
%
plot(x, Yp2, '-r', 'DisplayName', 'Fit');
text(1.1, 10, strcat('Slope in Log-Log Space =', num2str(Bp(1))), 'Interpreter', 'none');
legend
Which yields this plot:
untitled.jpg
  1 Kommentar
Angie Brulc
Angie Brulc am 7 Mär. 2022
Hello,
I'm a random student working on processing data for a lab and just wanted to let you know this was incredibly helpful to me. Thank you!

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