how to fill gaps in a matrix with a numbers using interpolation to develop a contour.
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
M.S. Khan
am 27 Jul. 2019
Kommentiert: M.S. Khan
am 30 Jul. 2019
M =
0 0 0
0 0 3
0 3 0
3 0 3
0 3 0
0 0 3
3 0 0
0 0 0
in this M matrix, using interpolation i want to fill gaps with 3s between any 3s. for example, in first column, first 3 is in the 4th row and last 3 is in the 7th row. i want to fill rows 5 and 6 also with 3s. same for other columns.
Thanks and regards for all cooperation
1 Kommentar
Akzeptierte Antwort
Andrei Bobrov
am 27 Jul. 2019
Bearbeitet: Andrei Bobrov
am 27 Jul. 2019
M(cumsum(M) & cumsum(M,1,'reverse')) = 3;
or for:
M =[0 0 0; 2 2 3; 3 3 0; 0 0 0; 3 3 0; 2 2 3; 0 0 0; 3 3 2; 0 0 0; 3 3 3];
s = join(string(M)','');
[a,b] = regexp(s,'30+3');
lo = false(size(M));
for ii = 1:numel(a)
for jj = 1:numel(a{ii})
lo(a{ii}(jj)+1:b{ii}(jj)-1,ii) = true;
end
end
M(lo) = 3;
Weitere Antworten (1)
KALYAN ACHARJYA
am 27 Jul. 2019
Bearbeitet: KALYAN ACHARJYA
am 27 Jul. 2019
M =[0 0 0
0 0 3
0 3 0
3 0 3
0 3 0
0 0 3
3 0 0
0 0 0]
[rows colm]=size(M);
for i=1:colm
idx=find(M(:,i)==3);
idx_update=idx(1):1:idx(end);
M(idx_update,i)=3;
end
M
Loop can be avoided. Wait for experts comments.
Result:
M =
0 0 0
0 0 3
0 3 3
3 3 3
3 3 3
3 0 3
3 0 0
0 0 0
5 Kommentare
Siehe auch
Kategorien
Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!