specific pattern from the file name
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I want to extract the project number from the file name
example the file fame is: 'abcdd-22_Z12'
the project number should be Z12 for sure it is dynamic name could in the next file name Z11 for intance.
which expression I should use
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Walter Roberson
am 26 Jul. 2019
[~, basename, ext] = fileparts(FileName);
parts = strsplit(basename, '_');
project = parts{end};
In some cases this can be simplified: for example if the directory and extension are already removed from FileName then
project = regexp(FileName, '(?<=_).*', 'match');
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ayman mounir
am 27 Jul. 2019
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Mehr zu File Operations finden Sie in Hilfe-Center und File Exchange
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