Fill an array in a for loop, with change of dimension

Hi, I have the following code and I have to fill the array T with y every loop.

y=zeros();
t=0;
nraw=420
for kk = 1:nraw
for   iii = 1:length(comb)-1  %% NON MI PIACE IL MENO 1
   
    t=t+1;
    if comb(t) == comb(t+1) 
       y(iii) = 1
    else
       y(iii) = 2
    end
end
T(kk,:)=y
end

The main problem is that length(comb) change every time, and so filling T I receive the following error

Unable to perform assignment because the size of the left side is 1-by-4 and the size of the right side
is 1-by-3.

Error in TAMBURILIMITATI2507 (line 150)
T(kk,:)=y

In fact, for the first iteration length(comb) was 5, but when become 4 the for cycle failed cause I cannot fill T

Do you know how to fix this case?

Answer 1

[KALYAN ACHARJYA]

"Fill an array in a for loop, with change of dimension"

Use cell array

Example

a={};
for i=1:...
a{i}=
end

Now a{1},a{2} can be any size within loop

Resultant may be look like

a={ array1 array2 array 3 array 4}

Here array1 array2 array 3 array 4...can have any sizes

[luca]

Ok it works. But now it possible to convert the cell array again in a normal array?

Cause as final rsult I need the array

[KALYAN ACHARJYA]

You can mix up all cell array elemnts, but how you distinguish, which array belongs to which part?

Please look on the link (difference between array and cell array)

"But now it possible to convert the cell array again in a normal array?"

Use cell2mat (Convert cell array to ordinary array)

Hope it helps!

[luca]

I've already tried to use cell2mat but it mix all:

If I've obtained a cell array T of 1*4 cell

T= [2221] [2221] [212] [1222]

And I write A=cell2mat(T)

I obtain

C= 222122212121222 of dimension 1*15

what i want is

C= [2221 ; 2221; 212;1222]

What can I do?

[KALYAN ACHARJYA]

C= [2221 ; 2221; 212;1222]
%....^Is this single number?

Suppose you are getting

C={[2 2 2 2]; [2 2 2 1];[2 1 2]; [1 2 2 2]}

Now you want to

C= [2221 ; 2221; 212;1222];

Right?

[KALYAN ACHARJYA]

If that is the case

C={[2 2 2 2]; [2 2 2 1];[2 1 2]; [1 2 2 2]}; % See C is here cell array
for i=1:length(C);
    validateattributes(C{i},{'numeric'},{'integer','nonnegative','<',10});
    result(i)=polyval(C{i}, 10);
end

Command Window

>> result
result =
        2222        2221         212        1222

Please Note: I have answered 2nd part from here (@Guillaume)

Hope It Helps!

[luca]

slightly different

I have

C={[2 2 2 2], [2 2 2 1], [2 1 2] , [1 2 2 2]}

with "," and not ";". So I have a 1*4 cell

and I want

D= [2,2,2,1 ; 2,2,2,1 ; 2,1,2 ; 1,2,2,2];

The problem is that in D the dimension of arrays being concatened are not consistent. So maybe is not possible to obtain such array.

Is there a way to do it?

[KALYAN ACHARJYA]

Please look here A=[1,2,3] is same as A=[1 2 3];

Also D=A' is same as A=[1;2;3]

>> A=[1,2,2]
A =
     1     2     2
>> A=[1 2 3]
A =
     1     2     3
>> B=[1;2;3]
B =
     1
     2
     3
>> D=A'
D =
     1
     2
     3
>> 

[KALYAN ACHARJYA]

Also D=[2,2,2,1 ; 2,2,2,1 ; 2,1,2 ; 1,2,2,2]; is not allowed becasue third row having 3 elements only (Varying array size to use Cell array is always recomended)

, means space and ; menas new row

Hope It helps!

[luca]

is it possibile to insert a 0 where there is the fourth element missed and so enable to get a result?

[KALYAN ACHARJYA]

Yes, do it (if required) during array calculations within loop, make them all array having 4 length, lesser fill with 0.

But I have no idea, why you are intended to doing so.

Good Luck!