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Why are condition2 condition3 and condition4 not logical?

2 Ansichten (letzte 30 Tage)
a=0.336;
Ta=9.476;
Te=1.208;
Tw=1.498;
eqh=[0.661;0.619;0.568];
ex=[-1.24;-1.346;-1.441];
en=-ex;
ey=[0.376;0.705;0.968];
eqx=[-0.309;-0.357;-0.392];
eh=[1.594;1.583;1.545];
eyqh=[0.642;0.78;0.897];
a0=a*Ta*Te^2;
r = -100:1:100;
[bt,Td]=meshgrid(r);
i=1;
figure('Name','Stable');
Kp=1./bt;
exqh(i)=en(i).*eqh(i)+eqx(i).*eh(i);
Ki=1./(bt.*Td);
a1=Ta.*Tw.*eqh(i)+a.*Te^2.*en(i)+a.*Te^2.*ey(i).*Kp;
a2=a.*Te^2.*Ki*ey(i)+Ta+Tw.*exqh(i)-eyqh(i).*Kp.*Tw;
a3=en(i)+ey(i).*Kp-eyqh(i).*Ki.*Tw;
a4=ey(i).*Ki;
condition1 =a1>0; output = ones(length(r));condition2=zeros(size(condition1));condition3=zeros(size(condition1));condition4=zeros(size(condition1));
for j=1:numel(a1)
condition2(j)=det([a1(j) a0;a3(j) a2(j)])>0;
condition3(j) =det([a1(j) a0 0;a3(j) a2(j) a1(j);0 a4(j) a3(j)])>0;
condition4(j)=det([a1(j) a0 0 0;a3(j) a2(j) a1(j) a0;0 a4(j) a3(j) a2(j);0 0 0 a4(j)])>0;
end
output(~(condition1 & condition2 & condition3 & condition4)) = 0;
imshow(output, 'xdata', r, 'ydata', r);
axis on;
Why are condition2 condition3 and condition4 not logical?

Akzeptierte Antwort

Image Analyst
Image Analyst am 22 Jul. 2019
You defined them to be doubles by instantiating them with the zeros() function. Try using false() instead of zeros():
condition2 = false(size(condition1));
condition3 = false(size(condition1));
condition4 = false(size(condition1));
  2 Kommentare
zhenyu zeng
zhenyu zeng am 23 Jul. 2019
Thanks, I know now.l
Image Analyst
Image Analyst am 23 Jul. 2019
Please, can you then "Accept this answer" by clicking on that link on this page? Thanks in advance.

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